TLINEARSUBST
FILE INFORMATION
FILENAME(S): TLINEARSUBST
FILE TYPE(S): PRG
FILE SIZE: 1K
FIRST SEEN: 2025-10-19 22:49:59
APPEARS ON: 1 disk(s)
FILE HASH
187ec13ba5119a90ca2f0afda0a7e11277c66a9ef1eb2127c5d933957e175604
FOUND ON DISKS (1 DISKS)
| DISK TITLE | FILENAME | FILE TYPE | COLLECTION | TRACK | SECTOR | ACTIONS |
|---|---|---|---|---|---|---|
| SLAVE | TLINEARSUBST | PRG | Radd Maxx | 26 | 10 | DOWNLOAD FILE |
FILE CONTENT & ANALYSIS
00000000: 31 00 31 00 04 02 AA 03 00 00 00 00 AA CA 10 F7 |1.1.............| 00000010: AD B1 AA 8D 57 AA 20 D4 A7 AD B3 AA F0 09 48 20 |....W. .......H | 00000020: 9D A6 68 A0 00 91 40 20 5B A7 AD 5F AA D0 20 A2 |..h...@ [.._.. .| 00000030: 2F BD 51 9E 9D D0 03 CA 10 F7 AD 53 9E 8D F3 03 |/.Q........S....| 00000040: 49 A5 8D F4 03 AD 52 9E 8D F2 03 A9 06 D0 05 AD |I.....R.........| 00000050: 62 AA F0 06 8D 5F AA 4C 80 A1 60 4C BF 9D 4C 84 |b...._.L..`L..L.| 00000060: 9D 4C FD AA 4C B5 B7 AD 0F 9D AC 0E 9D 60 AD C2 |.L..L........`..| 00000070: AA AC C1 AA 60 4C 51 A8 EA EA 4C 59 FA 4C 65 FF |....`LQ...LY.Le.| 00000080: 4C 58 FF 4C 65 FF 4C 65 FF 65 FF 20 D1 9E AD 51 |LX.Le.Le.e. ...Q| 00000090: AA F0 15 48 AD 5C AA 91 28 68 30 03 4C 26 A6 20 |...H.\..(h0.L&. | 000000A0: EA 9D A4 24 A9 60 91 28 AD B3 AA F0 03 20 82 A6 |...$.`.(..... ..| 000000B0: A9 03 8D 52 AA 20 BA 9F 20 BA 9E 8D 5C AA 8E 5A |...R. .. ...\..Z| 000000C0: AA 4C B3 9F 6C 38 00 20 D1 9E AD 52 AA 0A AA BD |.L..l8. ...R....| 000000D0: 11 9D 48 BD 10 9D 48 AD 5C AA 60 8D 5C AA 8E 5A |..H...H.\.`.\..Z| 000000E0: AA 8C 5B AA BA E8 E8 8E 59 AA A2 03 BD 53 AA 95 |..[.....Y....S..| 000000F0: 36 CA 10 F8 60 89 EE F3 89 EE F0 9E F4 9E 0A E5 |6...`...........| 00000100: 74 89 EE F3 9E F7 9E 0A E5 89 EE F5 89 EE F2 89 |t...............| 00000110: EE EF 9E F3 9E 0A E5 74 89 EE F2 89 EE EF 9E F3 |.......t........| 00000120: 9E 0A E5 74 00 89 EE F9 9E 40 9F 89 EE F3 89 EE |...t.....@......| 00000130: F0 9E F4 9E 0A E5 74 00 89 89 89 EE F0 9E F4 9E |......t.........| 00000140: 0A E5 74 00 89 EE FA 9E 41 9F 89 89 EE EF 9E F3 |..t.....A.......| 00000150: 9E 0A E5 74 00 89 EE F9 9E 40 9F DC E4 6E 00 6D |...t.....@...n.m| 00000160: A8 74 6C 69 6E 65 61 72 73 75 62 73 74 69 74 75 |.tlinearsubstitu| 00000170: 74 69 6F 6E 00 28 01 01 00 39 9F 37 9E 01 00 01 |tion.(...9.7....| 00000180: 01 00 01 00 49 9F 01 00 00 01 01 00 9F 01 00 06 |....I...........| 00000190: 4D 28 4E 3B 28 4E 38 9F 40 9F 3E 9E 50 00 FF FF |M(N;(N8.@.>.P...| 000001A0: 00 00 5C A8 20 D0 DA A7 5B A8 1E 00 00 A8 FF FF |..\. ...[.......| 000001B0: 02 00 06 00 07 A3 DA A7 DA A7 89 EE 5E 9F 6A 9F |............^.j.| 000001C0: C9 E1 5D A9 DA A7 BB B5 00 00 00 00 03 00 89 EE |..].............| 000001D0: 72 9F 7C 9F 53 E1 E1 A0 00 00 01 00 01 00 00 00 |r.|.S...........| 000001E0: 57 49 84 9F 90 9F 88 9E E1 A0 00 00 0C 62 00 42 |WI...........b.B| 000001F0: 11 42 11 FF A0 48 99 9F A1 9F 9F 9E 08 0C 62 E1 |.B...H........b.| 00000200: A0 5E 41 14 26 52 65 77 72 69 74 65 20 6F 6E 65 |.^A.&Rewrite one| 00000210: 20 6F 66 20 74 68 65 20 65 71 75 61 74 69 6F 6E | of the equation| 00000220: 73 20 73 6F 00 74 68 61 74 20 6F 6E 65 20 76 61 |s so.that one va| 00000230: 72 69 61 62 6C 65 20 69 73 20 65 78 70 72 65 73 |riable is expres| 00000240: 73 65 64 20 69 6E 00 74 65 72 6D 73 20 6F 66 20 |sed in.terms of | 00000250: 74 68 65 20 6F 74 68 65 72 2E 20 28 4F 6E 65 20 |the other. (One | 00000260: 76 61 72 69 61 62 6C 65 00 73 74 61 6E 64 73 20 |variable.stands | 00000270: 61 6C 6F 6E 65 20 6F 6E 20 6F 6E 65 20 73 69 64 |alone on one sid| 00000280: 65 20 6F 66 20 74 68 65 00 65 71 75 61 74 69 6F |e of the.equatio| 00000290: 6E 2E 29 00 26 55 73 65 20 74 68 65 20 65 78 70 |n.).&Use the exp| 000002A0: 72 65 73 73 69 6F 6E 20 66 6F 75 6E 64 20 69 6E |ression found in| 000002B0: 20 53 54 45 50 20 31 00 61 73 20 61 20 73 75 62 | STEP 1.as a sub| 000002C0: 73 74 69 74 75 74 65 20 66 6F 72 20 69 74 73 20 |stitute for its | 000002D0: 76 61 72 69 61 62 6C 65 00 69 6E 20 74 68 65 20 |variable.in the | 000002E0: 73 65 63 6F 6E 64 20 65 71 75 61 74 69 6F 6E 2E |second equation.| 000002F0: 00 26 53 6F 6C 76 65 20 74 68 65 20 72 65 73 75 |.&Solve the resu| 00000300: 6C 74 69 6E 67 20 65 71 75 61 74 69 6F 6E 20 74 |lting equation t| 00000310: 6F 00 66 69 6E 64 20 74 68 65 20 76 61 6C 75 65 |o.find the value| 00000320: 20 6F 66 20 74 68 65 20 66 69 72 73 74 00 76 61 | of the first.va| 00000330: 72 69 61 62 6C 65 2E 20 00 26 46 69 6E 64 20 74 |riable. .&Find t| 00000340: 68 65 20 73 65 63 6F 6E 64 20 76 61 72 69 61 62 |he second variab| 00000350: 6C 65 20 62 79 00 73 75 62 73 74 69 74 75 74 69 |le by.substituti| 00000360: 6E 67 20 74 68 65 20 76 61 6C 75 65 20 66 6F 75 |ng the value fou| 00000370: 6E 64 20 69 6E 00 53 54 45 50 20 33 20 69 6E 20 |nd in.STEP 3 in | 00000380: 6F 6E 65 20 6F 66 20 74 68 65 20 6F 72 69 67 69 |one of the origi| 00000390: 6E 61 6C 00 65 71 75 61 74 69 6F 6E 73 2C 20 61 |nal.equations, a| 000003A0: 6E 64 20 73 6F 6C 76 65 2E 00 00 00 00 00 00 00 |nd solve........| 000003B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000003C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000003D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000003E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000003F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................|
1.1..........J......W. T......H ..H ..@ [.._.P ./.Q..P.J...S....I.....R......P.. B...._.L..`L..L..L..L........`.B..A.`LQ. ..LY.LE.LX.LE.LE.E. Q..Q...H.\..(H0.L&. ...$.`.(..... .....R. .. ...\..Z.L..L8. Q..R......H...H.\.`.\..Z..[.....Y....S.. 6J..`...........T......................T ...........T.....@............T......... ..T.....A..........T.....@...N.M.TLINEAR SUBSTITUTION.(...9.7........I........... M(N;(N8.@.>.P.....\. PZ.[.............Z. Z...^.J.I.].Z...........R.|.S.. ........ WI....... ...B.B.B.. H........B. ^A.&REW RITE ONE OF THE EQUATIONS SO.THAT ONE VA RIABLE IS EXPRESSED IN.TERMS OF THE OTHE R. (ONE VARIABLE.STANDS ALONE ON ONE SID E OF THE.EQUATION.).&USE THE EXPRESSION FOUND IN STEP 1.AS A SUBSTITUTE FOR ITS VARIABLE.IN THE SECOND EQUATION..&SOLVE THE RESULTING EQUATION TO.FIND THE VALUE OF THE FIRST.VARIABLE. .&FIND THE SECON D VARIABLE BY.SUBSTITUTING THE VALUE FOU ND IN.STEP 3 IN ONE OF THE ORIGINAL.EQUA TIONS, AND SOLVE........................ ........................................ ........................
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