DIST4L4
FILE INFORMATION
FILENAME(S): DIST4L4
FILE TYPE(S): PRG
FILE SIZE: 6.7K
FIRST SEEN: 2025-10-19 22:48:55
APPEARS ON: 1 disk(s)
FILE HASH
36ca8d5b607949336166d500e3692f7c60e9b7622f6292452333ff876a0ad5f3
FOUND ON DISKS (1 DISKS)
| DISK TITLE | FILENAME | FILE TYPE | COLLECTION | TRACK | SECTOR | ACTIONS |
|---|---|---|---|---|---|---|
| HHM 100785 43S1 | DIST4L4 | PRG | Radd Maxx | 7 | 2 | DOWNLOAD FILE |
FILE CONTENT & ANALYSIS
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000009B0: 77 20 70 72 6F 62 6C 65 6D 2E 29 40 66 41 6D 79 |w problem.)@fAmy|
000009C0: 20 64 72 6F 76 65 20 36 30 30 20 6D 69 6C 65 73 | drove 600 miles|
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00000A60: 69 2F 68 72 3F 00 46 61 73 74 00 53 6C 6F 77 00 |i/hr?.Fast.Slow.|
00000A70: 41 6D 79 20 64 72 6F 76 65 20 36 30 30 20 6D 69 |Amy drove 600 mi|
00000A80: 6C 65 73 20 61 74 20 74 77 6F 20 72 61 74 65 73 |les at two rates|
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00000B00: 65 20 73 75 6D 20 6F 66 20 68 65 72 20 46 61 73 |e sum of her Fas|
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00000B30: 20 74 68 65 20 54 6F 74 61 6C 20 64 69 73 74 61 | the Total dista|
00000B40: 6E 63 65 2E 00 60 44 66 20 2B 20 44 73 20 3D 20 |nce..`Df + Ds = |
00000B50: 54 6F 74 61 6C 27 20 73 68 6F 77 73 20 74 68 61 |Total' shows tha|
00000B60: 74 20 74 68 65 20 73 75 6D 20 6F 66 20 68 65 72 |t the sum of her|
00000B70: 20 53 6C 6F 77 20 61 6E 64 20 46 61 73 74 20 64 | Slow and Fast d|
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00000BB0: 6F 74 61 6C 00 54 68 65 20 73 75 6D 20 6F 66 20 |otal.The sum of |
00000BC0: 68 65 72 20 46 61 73 74 20 61 6E 64 20 53 6C 6F |her Fast and Slo|
00000BD0: 77 20 64 69 73 74 61 6E 63 65 73 20 69 73 20 65 |w distances is e|
00000BE0: 71 75 61 6C 20 74 6F 20 74 68 65 20 54 6F 74 61 |qual to the Tota|
00000BF0: 6C 20 64 69 73 74 61 6E 63 65 2E 00 60 44 66 20 |l distance..`Df |
00000C00: 2B 20 44 73 20 3D 20 54 6F 74 61 6C 27 20 73 68 |+ Ds = Total' sh|
00000C10: 6F 77 73 20 74 68 61 74 20 74 68 65 20 73 75 6D |ows that the sum|
00000C20: 20 6F 66 20 68 65 72 20 53 6C 6F 77 20 61 6E 64 | of her Slow and|
00000C30: 20 46 61 73 74 20 64 69 73 74 61 6E 63 65 73 20 | Fast distances |
00000C40: 69 73 20 65 71 75 61 6C 20 74 6F 20 74 68 65 20 |is equal to the |
00000C50: 54 6F 74 61 6C 20 64 69 73 74 61 6E 63 65 2E 00 |Total distance..|
00000C60: 6D 69 2F 68 72 00 34 00 6D 69 2F 68 72 00 68 6F |mi/hr.4.mi/hr.ho|
00000C70: 75 72 73 2E 20 28 60 68 72 27 29 00 32 00 68 72 |urs. (`hr').2.hr|
00000C80: 00 6D 69 6C 65 73 2E 20 28 60 6D 69 27 29 00 32 |.miles. (`mi').2|
00000C90: 00 6D 69 00 26 68 41 6D 79 20 64 72 6F 76 65 20 |.mi.&hAmy drove |
00000CA0: 36 30 30 20 6D 69 6C 65 73 26 68 2E 00 54 68 65 |600 miles&h..The|
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00000CC0: 64 72 69 76 65 6E 20 69 73 20 60 36 30 30 27 20 |driven is `600' |
00000CD0: 6D 69 6C 65 73 2E 00 36 30 30 00 41 6D 79 20 64 |miles..600.Amy d|
00000CE0: 72 6F 76 65 20 36 30 30 20 6D 69 6C 65 73 20 69 |rove 600 miles i|
00000CF0: 6E 20 26 68 31 35 20 68 6F 75 72 73 26 68 2E 00 |n &h15 hours&h..|
00000D00: 54 68 65 20 74 6F 74 61 6C 20 74 69 6D 65 20 69 |The total time i|
00000D10: 73 20 60 31 35 27 20 68 6F 75 72 73 2E 00 31 34 |s `15' hours..14|
00000D20: 00 31 35 00 26 68 53 68 65 20 73 74 61 72 74 65 |.15.&hShe starte|
00000D30: 64 20 64 72 69 76 69 6E 67 20 61 74 20 35 30 20 |d driving at 50 |
00000D40: 6D 69 2F 68 72 26 68 00 54 68 65 20 66 61 73 74 |mi/hr&h.The fast|
00000D50: 20 72 61 74 65 20 69 73 20 60 35 30 27 20 6D 69 | rate is `50' mi|
00000D60: 2F 68 72 2E 00 37 00 35 30 00 53 68 65 20 68 61 |/hr..7.50.She ha|
00000D70: 64 20 74 6F 20 73 6C 6F 77 20 64 6F 77 6E 20 74 |d to slow down t|
00000D80: 6F 20 26 68 32 35 20 6D 69 2F 68 72 26 68 2E 00 |o &h25 mi/hr&h..|
00000D90: 54 68 65 20 73 6C 6F 77 20 72 61 74 65 20 69 73 |The slow rate is|
00000DA0: 20 60 32 35 27 20 6D 69 2F 68 72 2E 00 38 00 32 | `25' mi/hr..8.2|
00000DB0: 35 00 74 68 65 20 6E 75 6D 62 65 72 20 6F 66 20 |5.the number of |
00000DC0: 68 6F 75 72 73 20 73 68 65 20 74 72 61 76 65 6C |hours she travel|
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00000DE0: 68 65 20 72 61 74 65 73 00 69 73 3A 20 22 48 6F |he rates.is: "Ho|
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00000E10: 72 3F 22 00 74 68 65 20 53 6C 6F 77 20 64 72 69 |r?".the Slow dri|
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00000E40: 20 41 6D 79 20 64 72 6F 76 65 20 61 74 20 32 35 | Amy drove at 25|
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00000E70: 69 6D 65 20 41 6D 79 20 64 72 6F 76 65 20 61 74 |ime Amy drove at|
00000E80: 20 35 30 20 6D 69 2F 68 72 00 74 68 65 20 74 69 | 50 mi/hr.the ti|
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00000EA0: 32 35 20 6D 69 2F 68 72 29 00 53 68 65 20 64 72 |25 mi/hr).She dr|
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00000EC0: 6F 66 20 31 35 20 68 6F 75 72 73 2E 20 46 6F 72 |of 15 hours. For|
00000ED0: 20 22 26 76 22 20 68 72 73 20 73 68 65 20 64 72 | "&v" hrs she dr|
00000EE0: 6F 76 65 20 73 6C 6F 77 6C 79 2E 20 46 6F 72 20 |ove slowly. For |
00000EF0: 74 68 65 20 72 65 6D 61 69 6E 69 6E 67 20 74 69 |the remaining ti|
00000F00: 6D 65 2C 20 60 31 35 2D 26 76 27 2C 20 73 68 65 |me, `15-&v', she|
00000F10: 20 64 72 6F 76 65 20 66 61 73 74 2E 00 31 32 00 | drove fast..12.|
00000F20: 31 35 2D 26 76 00 5C 66 30 35 2A 20 20 5C 66 30 |15-&v.\f05* \f0|
00000F30: 37 54 69 6D 65 20 20 5C 66 31 34 3D 20 44 69 73 |7Time \f14= Dis|
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00000F50: 20 20 5C 66 30 37 28 31 35 2D 26 76 29 27 20 5C | \f07(15-&v)' \|
00000F60: 66 31 34 3D 20 46 61 73 74 20 64 69 73 74 61 6E |f14= Fast distan|
00000F70: 63 65 00 35 30 28 31 35 2D 26 76 00 5C 66 30 35 |ce.50(15-&v.\f05|
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00000FA0: 20 5C 66 30 35 2A 20 20 5C 66 30 37 20 26 76 27 | \f05* \f07 &v'|
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00000FD0: 66 00 73 00 54 6F 74 61 6C 00 66 00 35 30 28 31 |f.s.Total.f.50(1|
00000FE0: 35 2D 26 76 29 00 73 00 32 35 26 76 00 36 30 30 |5-&v).s.25&v.600|
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00001000: 2B 20 53 6C 6F 77 20 64 69 73 74 2E 20 20 5C 66 |+ Slow dist. \f|
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00001030: 20 20 20 20 32 35 26 76 20 5C 66 32 35 3D 20 36 | 25&v \f25= 6|
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00001050: 26 76 3D 36 30 30 00 36 00 48 6F 77 20 6C 6F 6E |&v=600.6.How lon|
00001060: 67 20 64 69 64 20 73 68 65 20 64 72 69 76 65 20 |g did she drive |
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00001120: 74 20 35 30 20 6D 69 2F 68 72 2E 00 31 32 00 39 |t 50 mi/hr..12.9|
00001130: 00 74 68 65 20 46 61 73 74 20 64 69 73 74 61 6E |.the Fast distan|
00001140: 63 65 00 35 30 28 31 35 2D 26 76 29 20 69 73 20 |ce.50(15-&v) is |
00001150: 74 68 65 20 46 61 73 74 20 64 69 73 74 61 6E 63 |the Fast distanc|
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00001280: 20 67 6F 69 6E 67 20 34 35 20 6D 69 2F 68 72 2E | going 45 mi/hr.|
00001290: 20 49 66 20 74 68 65 20 65 6E 74 69 72 65 20 74 | If the entire t|
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000012E0: 33 33 20 6D 69 6C 65 73 20 61 74 20 74 77 6F 20 |33 miles at two |
000012F0: 64 69 66 66 65 72 65 6E 74 20 72 61 74 65 73 2E |different rates.|
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00001350: 67 20 64 69 73 74 00 77 00 72 00 54 68 65 20 73 |g dist.w.r.The s|
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000013A0: 77 2B 44 72 20 3D 20 54 6F 74 61 6C 27 20 73 68 |w+Dr = Total' sh|
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000013D0: 61 6E 64 20 72 69 64 69 6E 67 20 64 69 73 74 61 |and riding dista|
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00001440: 73 20 74 68 65 20 54 6F 74 61 6C 20 64 69 73 74 |s the Total dist|
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00001460: 6F 74 61 6C 27 20 73 68 6F 77 73 20 74 68 61 74 |otal' shows that|
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00001490: 6E 67 20 64 69 73 74 61 6E 63 65 73 20 69 73 20 |ng distances is |
000014A0: 65 71 75 61 6C 20 74 6F 20 74 68 65 20 54 6F 74 |equal to the Tot|
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000014D0: 20 28 60 68 72 27 29 2E 00 32 00 68 72 00 6D 69 | (`hr')..2.hr.mi|
000014E0: 6C 65 73 20 28 60 6D 69 27 29 2E 00 32 00 6D 69 |les (`mi')..2.mi|
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00001550: 61 6B 65 73 20 37 32 20 6D 69 6E 2E 26 68 20 28 |akes 72 min.&h (|
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000015C0: 60 31 2E 32 27 20 68 6F 75 72 73 2E 00 31 34 00 |`1.2' hours..14.|
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00001600: 6C 6B 69 6E 67 20 72 61 74 65 20 69 73 20 60 33 |lking rate is `3|
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00001640: 48 69 73 20 72 69 64 69 6E 67 20 72 61 74 65 20 |His riding rate |
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00001730: 46 6F 72 20 26 76 20 68 72 73 2C 20 68 65 20 77 |For &v hrs, he w|
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00001750: 74 68 65 20 72 65 6D 61 69 6E 69 6E 67 20 74 69 |the remaining ti|
00001760: 6D 65 2C 20 60 31 2E 32 2D 26 76 27 20 68 72 73 |me, `1.2-&v' hrs|
00001770: 2C 20 68 65 20 77 61 73 20 6F 6E 20 74 68 65 20 |, he was on the |
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00001790: 00 5C 66 30 35 2A 20 20 5C 66 30 37 54 69 6D 65 |.\f05* \f07Time|
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00001880: 3D 20 33 33 00 20 20 20 20 60 33 26 76 20 20 5C |= 33. `3&v \|
00001890: 66 31 35 2B 20 34 35 28 31 2E 32 2D 26 76 29 20 |f15+ 45(1.2-&v) |
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000018B0: 35 28 31 2E 32 2D 26 76 29 3D 33 33 00 31 2F 32 |5(1.2-&v)=33.1/2|
000018C0: 00 48 6F 77 20 66 61 72 20 64 6F 65 73 20 68 65 |.How far does he|
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00001920: 20 74 69 6D 65 00 22 26 76 22 20 72 65 70 72 65 | time."&v" repre|
00001930: 73 65 6E 74 73 20 74 68 65 20 74 69 6D 65 20 68 |sents the time h|
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000019A0: 22 20 72 65 70 72 65 73 65 6E 74 73 20 74 68 65 |" represents the|
000019B0: 20 74 69 6D 65 20 68 65 20 73 70 65 6E 74 20 72 | time he spent r|
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00001A10: 69 6E 67 20 64 69 73 74 61 6E 63 65 00 34 35 28 |ing distance.45(|
00001A20: 31 2E 32 2D 26 76 29 20 72 65 70 72 65 73 65 6E |1.2-&v) represen|
00001A30: 74 73 20 74 68 65 20 64 69 73 74 61 6E 63 65 20 |ts the distance |
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00001A50: 72 61 69 6E 2E 20 53 69 6E 63 65 20 26 76 3D 2E |rain. Since &v=.|
00001A60: 35 2C 20 74 68 65 20 64 69 73 74 61 6E 63 65 20 |5, the distance |
00001A70: 65 71 75 61 6C 73 20 2E 37 2A 34 35 2C 20 6F 72 |equals .7*45, or|
00001A80: 20 60 33 31 2E 35 27 20 6D 69 6C 65 73 2E 00 31 | `31.5' miles..1|
00001A90: 38 00 33 31 2E 35 00 77 61 6C 6B 69 6E 67 20 61 |8.31.5.walking a|
00001AA0: 6E 64 20 72 69 64 69 6E 67 00 33 33 20 6D 69 6C |nd riding.33 mil|
00001AB0: 65 73 00 7C 20 |es.| |
A@Q{}@DG04&D(1,U/MEAS)&C(2,{})&C(3,{})&
C(4,TOT.)&D(5,RATE)&D(10,TIME)&D(15,DIST
.)@RREAD@PREAD THE WHOLE PROBLEM. THINK:
WHAT ARE THE FACTS? WHAT IS BEING ASKED
? (PRESS ANY KEY TO CONTINUE.)@HWHAT ARE
THE FACTS? {}@HWHAT IS BEING ASKED? {}@
I(0)@RPLAN @PLET D{}={} AND D{}={}. WRIT
E AN EQUATION TO RELATE D{} AND D{} TO T
HE TOTAL DIST.@H{}@H{}@I(20,C0, )@PONE A
NSWER IS {}. CHANGE YOUR ANSWER IF IT IS
NOT EQUIVALENT. (PRESS RETURN)@H{}@H{}@
I(20,C0, )@RDATA ENTRY@PFILL IN THE UNIT
S BY WHICH RATE, TIME AND DISTANCE ARE M
EASURED.@HRATE IS COMMONLY MEASURED IN M
ILES PER HOUR(MI/HR), FEET PER SECOND(FT
/SEC), METERS PER MINUTE(M/MIN), ETC.@HT
HE RATE OF SPEED IN THIS PROBLEM IS MEAS
URED IN `{}'.@I(6,C{},{})@HTIME IS COMMO
NLY MEASURED IS SECONDS(SEC), MINUTES(MI
N), HOURS(HR), DAYS(DA), ETC.@HTIME IN T
HIS PROBLEM IS MEASURED IN {}@I(11,C{},{
})@HDISTANCE IS COMMONLY MEASURED IN FEE
T(FT), YARDS(YD), MILES(MI), METERS(M),
KILOMETERS(KM), ETC.@HDISTANCE IN THIS P
ROBLEM IS MEASURED IN {}@I(16,C{},{})@PE
NTER THE FACTS FROM THE PROBLEM INTO THE
GRID.@H{}@H{}@I(19,I,{})@H{}@H{}@I({},I
,{})@H{}@H{}@I({},I,{})@H{}@H{}@I({},I,{
})@PREPRESENT {}.@HSINCE THE QUESTION {}
, USE A VARIABLE TO REPRESENT {}.@HUSE A
VARIABLE, SUCH AS `{}' TO REPRESENT {}.
@I({},I,&V)@HREPRESENT {} IN TERMS OF "
&V" ({}.@H{}@I({},I,{})@RPARTS@PWRITE AN
EXPRESSION TO REPRESENT THE DISTANCE TR
AVELLED AT EACH RATE.@HRATE*TIME = DISTA
NCE@HRATE {} \N{}@I(17,I,{}))@HRATE*TIME
= DISTANCE@HRATE {} \N{}@I(18,I,{})@RWH
OLE&D(20, )@PSUBSTITUTE YOUR EXPRESSIONS
FOR {}, {} AND TOTAL IN THE EQUATION. \
NEQUATION : D{}+D{} = {}@HD{} = {}, D{}
= {} AND TOTAL = {}.@H{} \N{}@I(20,I,{})
@S@RCOMPUTE@PSOLVE THE EQUATION FOR "&V"
. USE PAPER AND PENCIL AND ENTER THE FIN
AL EQUATION, OR USE THE CALCULATOR.@HIS
OLATE "&V" ON ONE SIDE OF THE EQUATION.@
HTHE CALCULATOR SOLVES EQUATIONS FOR YOU
AND DISPLAYS THE STEPS IN THE SOLUTION.
@I(20,I,&V={})@PENTER YOUR ANSWERS TO TH
E PROBLEM IN THE GRID. REMEMBER THE QUES
TION. &Q{}&Q@HTHE {} IS EQUAL TO THE VAL
UE OF {}.@H&V = {}, SO {}.@I({},I,{}) @S
@RCHECK@PREREAD THE PROBLEM. CHECK YOUR
ANSWERS. EVALUATE THE REMAINING EXPRESSI
ONS IN THE GRID.@HSUBSTITUTE FOR "&V" IN
THE EXPRESSION FOR {}. THEN CALCULATE T
HE RESULT.@H{}@I({},I,{})@HSUBSTITUTE FO
R "&V" IN THE EXPRESSION FOR {}. THEN CA
LCULATE THE RESULT.@H{}@I({},I,{})@HSUBS
TITUTE FOR "&V" IN THE EXPRESSION FOR {}
. THEN CALCULATE THE RESULT.@H{}@I({},I,
{})&D(0,CHECK YOUR WORK. THE SUM OF THE
{} DISTANCES SHOULD EQUAL {}. ON TO A NE
W PROBLEM.)@FAMY DROVE 600 MILES IN 15 H
OURS. SHE STARTED DRIVING AT 50 MI/HR AN
D THEN BAD WEATHER FORCED HER TO SLOW DO
WN TO 25 MI/HR. FOR HOW MANY HOURS DID S
HE DRIVE AT 25 MI/HR?.FAST.SLOW.AMY DROV
E 600 MILES AT TWO RATES, 50 MI/HR AND 2
5 MI/HR..&HHOW MANY HOURS DID SHE DRIVE
AT 25 MI/HR?&H.F.AMY'S FAST DIST..S.HER
SLOW DIST.F.S.THE SUM OF HER FAST AND SL
OW DISTANCES IS EQUAL TO THE TOTAL DISTA
NCE..`DF + DS = TOTAL' SHOWS THAT THE SU
M OF HER SLOW AND FAST DISTANCES IS EQUA
L TO THE TOTAL DISTANCE..DF+DS=TOTAL.THE
SUM OF HER FAST AND SLOW DISTANCES IS E
QUAL TO THE TOTAL DISTANCE..`DF + DS = T
OTAL' SHOWS THAT THE SUM OF HER SLOW AND
FAST DISTANCES IS EQUAL TO THE TOTAL DI
STANCE..MI/HR.4.MI/HR.HOURS. (`HR').2.HR
.MILES. (`MI').2.MI.&HAMY DROVE 600 MILE
S&H..THE TOTAL DISTANCE DRIVEN IS `600'
MILES..600.AMY DROVE 600 MILES IN &H15 H
OURS&H..THE TOTAL TIME IS `15' HOURS..14
.15.&HSHE STARTED DRIVING AT 50 MI/HR&H.
THE FAST RATE IS `50' MI/HR..7.50.SHE HA
D TO SLOW DOWN TO &H25 MI/HR&H..THE SLOW
RATE IS `25' MI/HR..8.25.THE NUMBER OF
HOURS SHE TRAVELLED AT EACH OF THE RATES
.IS: "HOW LONG DID SHE TRAVEL AT 25 MI/H
R?".THE SLOW DRIVING TIME..S.THE NUMBER
OF HOURS AMY DROVE AT 25 MI/HR (THE SLOW
SPEED).13.THE TIME AMY DROVE AT 50 MI/H
R.THE TIME SHE DROVE AT 25 MI/HR).SHE DR
OVE FOR A TOTAL OF 15 HOURS. FOR "&V" HR
S SHE DROVE SLOWLY. FOR THE REMAINING TI
ME, `15-&V', SHE DROVE FAST..12.15-&V.\F
05* \F07TIME \F14= DISTANCE.`50 \F05*
\F07(15-&V)' \F14= FAST DISTANCE.50(15
-&V.\F05* \F07TIME \F12= DISTANCE.`25
\F05* \F07 &V' \F12= SLOW DISTANCE.25&
V.DF.DS.F.S.TOTAL.F.50(15-&V).S.25&V.600
.FAST DIST. \F12+ SLOW DIST. \F25= TOTA
L DIST..`50(15-&V) \F12+ 25&V \F25= 6
00'.50(15-&V)+25&V=600.6.HOW LONG DID SH
E DRIVE AT 25 MI/HR?.TIME FOR THE SLOW R
IDE."&V".6.SHE DROVE SLOWLY FOR `6' HOUR
S.13.6.THE FAST TIME.15-&V IS THE FAST T
IME. AND &V=6, SO 15-6 OR `9' IS THE NUM
BER OF HOURS SHE DROVE AT 50 MI/HR..12.9
.THE FAST DISTANCE.50(15-&V) IS THE FAST
DISTANCE. &V=6, SO 50(15-6) OR `450' IS
THE FAST DISTANCE..17.450.THE SLOW DIST
ANCE.25&V IS THE SLOW DISTANCE. &V=6, SO
25&V OR `150' IS THE FAST DISTANCE..18.
150.FAST AND SLOW.600.@FJAKE TRAVELS A T
OTAL OF 33 MI. TO WORK EACH DAY. HE WALK
S TO THE TRAIN STATION AT 3 MI/HR AND TH
EN TAKES A TRAIN GOING 45 MI/HR. IF THE
ENTIRE TRIP TAKES 72 MIN., HOW FAR DOES
HE WALK?.WALK.RIDE.JAKE TRAVELS 33 MILES
AT TWO DIFFERENT RATES. HIS TOTAL TIME
IS 72 MINUTES..&HHOW FAR DOES HE WALK?&H
.W.WALKING DIST..R.RIDING DIST.W.R.THE S
UM OF THE WALKING AND RIDING DISTANCES I
S THE TOTAL DISTANCE..`DW+DR = TOTAL' SH
OWS THAT THE SUM OF THE WALKING AND RIDI
NG DISTANCES IS EQUAL TO THE TOTAL DISTA
NCE..DW+DR = TOTAL.THE SUM OF THE WALKIN
G AND RIDING DISTANCES IS THE TOTAL DIST
ANCE..`DW+DR = TOTAL' SHOWS THAT THE SUM
OF THE WALKING AND RIDING DISTANCES IS
EQUAL TO THE TOTAL DISTANCE..MI/HR.4.MI/
HR.HOURS (`HR')..2.HR.MILES (`MI')..2.MI
.&HJAKE TRAVELS A TOTAL OF 33 MILES.&H.T
HE TOTAL NUMBER OF MILES IS `33'..33.&HT
HE ENTIRE TRIP TAKES 72 MIN.&H (REMEMBER
TIME IN THIS PROBLEM IS MEASURED IN HOU
RS.).THE TOTAL AMOUNT OF TIME IS 72 MINU
TES, OR `1.2' HOURS..14.1.2.&HHE WALKS T
O THE TRAIN AT 3 MI/HR&H..HIS WALKING RA
TE IS `3' MI/HR..7.3.THE TRAIN TRAVELS A
T &H45 MI/HR&H..HIS RIDING RATE IS `45'
MI/HR..8.45.THE AMOUNTS OF TIME HE SPENT
WALKING AND RIDING.BEING ASKED REFERS T
O WALKING.THE WALKING TIME.W.THE TIME SP
ENT WALKING.12.THE TIME SPENT ON THE TRA
IN.THE TIME SPENT WALKING).THE TOTAL TRI
P TOOK 1.2 HRS. FOR &V HRS, HE WAS WALKI
NG. FOR THE REMAINING TIME, `1.2-&V' HRS
, HE WAS ON THE TRAIN..13.1.2-&V.\F05*
\F07TIME \F12= DISTANCE.`3 \F05* \F0
9&V' \F12= WALKING DIST..3&V.\F05* \F1
0TIME \F15= DISTANCE.`45 \F05* \F07(1
.2-&V)' \F15= RIDING DIST.45(1.2-&V).DW.
DR.W.R.TOTAL.W.3&V.R.45(1.2-&V).33.WALKI
NG DIST. \F15+ RIDING DIST. \F30= 33.
`3&V \F15+ 45(1.2-&V) \F30= 33'.3&V+4
5(1.2-&V)=33.1/2.HOW FAR DOES HE WALK?.W
ALKING DISTANCE.3&V..5.HE WALKED .5*3, O
R `1.5' MILES.17.1.5.THE WALKING TIME."&
V" REPRESENTS THE TIME HE SPENT WALKING
AND &V = .5, SO HE WALKED FOR `.5' OR `1
/2' HOUR..12.1/2.THE RIDING TIME."1.2-&V
" REPRESENTS THE TIME HE SPENT RIDING ON
THE TRAIN AND &V=.5, SO HE RODE FOR 1.2
-.5, OR `.7'HOURS..13..7.THE RIDING DIST
ANCE.45(1.2-&V) REPRESENTS THE DISTANCE
HE RODE ON THE TRAIN. SINCE &V=.5, THE D
ISTANCE EQUALS .7*45, OR `31.5' MILES..1
8.31.5.WALKING AND RIDING.33 MILES.|
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