BUOYANCY.C3
FILE INFORMATION
FILENAME(S): BUOYANCY.C3
FILE TYPE(S): PRG
FILE SIZE: 21.9K
FIRST SEEN: 2025-10-20 14:32:11
APPEARS ON: 1 disk(s)
FILE HASH
50cc8e4b5394ffce7b98f43256b9fc28892f29da2fd9aa26d6cb7eb7346d271f
FOUND ON DISKS (1 DISKS)
| DISK TITLE | FILENAME | FILE TYPE | COLLECTION | TRACK | SECTOR | ACTIONS |
|---|---|---|---|---|---|---|
| PB DOMAIN 0006ED | BUOYANCY.C3 | PRG | Treasure Chest - Klaus Der Suhler | 19 | 0 | DOWNLOAD FILE |
FILE CONTENT & ANALYSIS
> DETECTED: COMMODORE BASIC PROGRAM (LOAD ADDRESS $0801)
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00000010: 20 2A 2A 20 4D 4C 20 53 54 4F 50 20 4B 45 59 20 | ** ML STOP KEY |
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00000780: 11 11 20 20 20 20 20 20 20 31 2E 20 20 20 42 55 |.. 1. BU|
00000790: 4F 59 41 4E 43 59 20 50 52 4F 42 4C 45 4D 53 22 |OYANCY PROBLEMS"|
000007A0: 00 CD 0F 40 01 3A 20 20 99 22 11 11 20 20 20 20 |...@.: .".. |
000007B0: 20 20 20 32 2E 20 20 20 53 54 55 44 45 4E 54 20 | 2. STUDENT |
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00000860: 45 53 53 20 41 20 4E 55 4D 42 45 52 20 4B 45 59 |ESS A NUMBER KEY|
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000008F0: 2D 45 4E 41 42 4C 45 20 53 54 4F 50 20 4B 45 59 |-ENABLE STOP KEY|
00000900: 20 41 4E 44 20 45 4E 44 2D 2D 2D 2D 2D 00 3F 11 | AND END-----.?.|
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00000A30: 12 C4 01 99 22 20 20 20 54 59 50 49 4E 47 20 59 |...." TYPING Y|
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00000A60: 20 54 48 45 20 43 4F 4D 50 55 54 45 52 20 54 4F | THE COMPUTER TO|
00000A70: 20 41 43 43 45 50 54 20 57 48 41 54 20 59 4F 55 | ACCEPT WHAT YOU|
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00000AC0: 22 00 EB 12 CC 01 99 22 20 20 20 54 4F 20 54 48 |"......" TO TH|
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00000C60: 20 20 20 54 48 49 53 20 50 52 4F 47 52 41 4D 20 | THIS PROGRAM |
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000054F0: 20 20 20 20 20 20 20 20 20 20 20 20 4D 45 4E 55 | MENU|
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00005530: 56 5D 03 11 99 22 11 11 20 20 20 20 31 2E 20 20 |V]...".. 1. |
00005540: 20 4D 41 53 53 20 2F 20 57 45 49 47 48 54 20 52 | MASS / WEIGHT R|
00005550: 45 56 49 45 57 22 00 77 5D 08 11 99 22 11 11 20 |EVIEW".w]...".. |
00005560: 20 20 20 32 2E 20 20 20 44 45 4E 53 49 54 59 20 | 2. DENSITY |
00005570: 52 45 56 49 45 57 22 00 99 5D 0D 11 99 22 11 11 |REVIEW"..]..."..|
00005580: 20 20 20 20 33 2E 20 20 20 42 55 4F 59 41 4E 43 | 3. BUOYANC|
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000055E0: 00 0A 5E 26 11 99 22 11 11 20 20 20 20 50 52 45 |..^&..".. PRE|
000055F0: 53 53 20 41 20 4E 55 4D 42 45 52 20 4B 45 59 20 |SS A NUMBER KEY |
00005600: 28 31 20 2D 20 34 29 20 22 3B 00 37 5E 2B 11 55 |(1 - 4) ";.7^+.U|
00005610: 4C B2 31 3A 55 53 24 B2 22 31 32 33 34 22 3A 8D |L.1:US$."1234":.|
00005620: 33 35 3A 8F 2D 2D 2D 49 4E 50 55 54 20 52 4F 55 |35:.---INPUT ROU|
00005630: 54 49 4E 45 2D 2D 2D 00 48 5E 2D 11 99 22 93 22 |TINE---.H^-.."."|
00005640: 3A 97 55 54 2C 55 4C 25 00 68 5E 30 11 91 C5 28 |:.UT,UL%.h^0...(|
00005650: 55 52 24 29 8D 31 33 36 30 2C 31 38 36 30 2C 32 |UR$).1360,1860,2|
00005660: 35 31 30 2C 34 34 39 30 00 83 5E 8A 11 99 22 11 |510,4490..^...".|
00005670: 11 11 11 20 20 20 20 20 20 20 20 20 20 20 20 D7 |... .|
00005680: 45 4C 4C 00 A4 5E 94 11 99 22 11 11 1D 1D 1D 1D |ELL..^..."......|
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000056A0: 4C 4C 2E 22 00 AD 5E 9E 11 8D 38 33 35 00 B6 5E |LL."..^...835..^|
000056B0: A8 11 89 33 30 30 00 CD 5E D0 11 4E B2 B5 28 34 |...300..^..N..(4|
000056C0: 30 AC BB 28 31 29 AA 31 30 29 AD 31 30 00 E5 5E |0..(1).10).10..^|
000056D0: DA 11 4B 47 B2 B5 28 31 30 30 AC 4E AD 39 2E 38 |..KG..(100.N.9.8|
000056E0: 29 AD 31 30 30 00 EB 5E E4 11 8E 00 06 5F 88 13 |).100..^....._..|
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00005710: 4C 00 41 5F 9C 13 20 99 22 20 20 20 20 20 20 20 |L.A_.. ." |
00005720: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 | |
00005730: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 | |
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00005770: 4E 24 2C 4C 29 3B 00 7C 5F C4 13 8E 00 00 00 |N$,L);.|_...... |
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THE AMOUNT OF MATERIAL IN AN".(#..."
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SOME PROBLEMS,".Q(..." TRY THIS ONE:.
"..(..." WHAT IS THE MASS OF AN OBJECT
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ACK TO THE".|*N.." MENU? (Y/N) ";:US$.
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850:.". GOOD, NOW TRY ONE THE OTHER WA
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;N;"N ?"..,..." (NUMBER ONLY) ";.7,...
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NO, THE ANSWER IS"KG"KG.":.835:.1790..
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"..,:.." TOPIC.":.835:.4340.T,D.UP.0:U
G$." DENSITY PG.":.850..,F..".
DENSITY MEASURES THE AMOUNT".$-I.." OF
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IFT WHILE IT IS".AA..." SUBMERGED. AS
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S SEEM TO WEIGH"..A..." LESS WHEN SUBM
ERGED UNDER A FLUID"..A..." THAN THEY
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HAT UNDER THE FLUID".3B(.." IS CALLED
THE BUOYANT FORCE.".\B2.." IT IS THE F
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OF THE SUBMERGED OBJECT.":.835:.850..CD
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.CN.." THE NEW PART IS THAT THE WEIGHT
"..CX.." OF THE FLUID THAT WAS DISPLAC
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KG' WEIGHS 9.8N. IF".NJ..." YOU KN
OW ONE OF 'M' OR 'W',"..J..." THEN
YOU KNOW...."..K..." 3. 'W'(IN AIR) -
'W'(IN FLUID) =".AK..." BUOYANT FOR
CE = 'W'(OF DIS-".\K..." PLACED FLU
ID."..K...".. REMEMBER THESE THREE REL
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AT HELP TO YOU.".FKL..835:.850..K...".
200G OF A MATERIAL WHOSE DEN-"..L..."
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IN A LIQUID. IF THE WEIGHT".IL!.." IN
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2. VOLUME OF THE LIQUID DISPLACED."..L
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.UMS.." COMPARE.":.835:.850..MX..".
OBJECT LIQUID..MB..
" ...... .......X
ML..". MASS(G) 200 ?
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SINCE WE KNOW 'D' & 'M' FOR".\O..." TH
E OBJECT, WE CAN FIND 'V'."..O...". W
HAT IS THE VOLUME OF THE"..O..." OBJEC
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W WE KNOW THE WEIGHT IN"..TW.." AIR AN
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