_  __   _  _         _ _     _      _           _           
  __| |/ /_ | || |     __| (_)___| | __ (_)_ __   __| | _____  __
 / _` | '_ \| || |_   / _` | / __| |/ / | | '_ \ / _` |/ _ \ \/ /
| (_| | (_) |__   _| | (_| | \__ \   <  | | | | | (_| |  __/>  < 
 \__,_|\___/   |_|    \__,_|_|___/_|\_\ |_|_| |_|\__,_|\___/_/\_\
                                                                 
            

MIXT1L4

FILE INFORMATION

FILENAME(S): MIXT1L4

FILE TYPE(S): PRG

FILE SIZE: 6.4K

FIRST SEEN: 2025-10-19 22:48:55

APPEARS ON: 1 disk(s)

FILE HASH

56e6e9c754e678f2778cb44960bcb6c00c9a1bca1babba7cccdd700f4e1048ef

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DISK TITLE FILENAME FILE TYPE COLLECTION TRACK SECTOR ACTIONS
HHM 100785 44S1 MIXT1L4 PRG Radd Maxx 6 0 DOWNLOAD FILE

FILE CONTENT & ANALYSIS

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00000E20: 27 00 26 76 2B 35 20 3D  20 31 2B 35 20 3D 20 60  |'.&v+5 = 1+5 = `|
00000E30: 36 27 2E 20 54 68 65 72  65 20 61 72 65 20 36 20  |6'. There are 6 |
00000E40: 67 61 6C 6C 6F 6E 73 20  6F 66 20 32 35 25 20 73  |gallons of 25% s|
00000E50: 6F 6C 75 74 69 6F 6E 00  36 00 61 6E 74 69 66 72  |olution.6.antifr|
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00000EA0: 28 26 76 2B 35 29 20 3D  20 2E 32 35 28 31 2B 35  |(&v+5) = .25(1+5|
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00000EE0: 2E 35 00 57 65 61 6B 20  61 6E 64 20 50 75 72 65  |.5.Weak and Pure|
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00000F30: 20 6D 65 6C 74 65 64 20  6E 69 63 6B 65 6C 2E 20  | melted nickel. |
00000F40: 48 6F 77 20 6D 75 63 68  20 63 6F 70 70 65 72 20  |How much copper |
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00000F90: 74 6F 20 63 72 65 61 74  65 20 61 20 62 72 61 73  |to create a bras|
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00001120: 65 72 00 70 6F 75 6E 64  73 20 6F 66 20 62 72 61  |er.pounds of bra|
00001130: 73 73 20 69 73 20 60 32  30 27 00 39 00 32 30 00  |ss is `20'.9.20.|
00001140: 50 75 72 65 20 63 6F 70  70 65 72 00 70 6F 75 6E  |Pure copper.poun|
00001150: 64 73 20 6F 66 20 50 75  72 65 20 63 6F 70 70 65  |ds of Pure coppe|
00001160: 72 00 60 70 27 20 74 6F  20 72 65 70 72 65 73 65  |r.`p' to represe|
00001170: 6E 74 20 74 68 65 20 6E  75 6D 62 65 72 20 6F 66  |nt the number of|
00001180: 20 70 6F 75 6E 64 73 20  6F 66 20 50 75 72 65 20  | pounds of Pure |
00001190: 63 6F 70 70 65 72 00 31  30 00 70 6F 75 6E 64 73  |copper.10.pounds|
000011A0: 00 74 68 65 20 23 20 6F  66 20 70 6F 75 6E 64 73  |.the # of pounds|
000011B0: 20 6F 66 20 50 75 72 65  20 63 6F 70 70 65 72 00  | of Pure copper.|
000011C0: 32 30 25 20 61 6E 64 20  74 68 65 20 50 75 72 65  |20% and the Pure|
000011D0: 20 63 6F 70 70 65 72 20  73 6F 6C 75 74 69 6F 6E  | copper solution|
000011E0: 73 00 60 26 76 2B 32 30  27 20 70 6F 75 6E 64 73  |s.`&v+20' pounds|
000011F0: 00 26 76 2B 32 30 00 63  6F 70 70 65 72 00 70 6F  |.&v+20.copper.po|
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00001220: 6B 00 2E 32 30 00 32 30  00 57 65 61 6B 00 2E 32  |k..20.20.Weak..2|
00001230: 30 2A 32 30 00 70 6F 75  6E 64 73 20 6F 66 20 50  |0*20.pounds of P|
00001240: 75 72 65 20 73 6F 6C 75  74 69 6F 6E 00 6C 62 00  |ure solution.lb.|
00001250: 6C 62 73 00 50 75 72 65  00 31 00 26 76 00 50 75  |lbs.Pure.1.&v.Pu|
00001260: 72 65 00 31 2A 26 76 00  70 6F 75 6E 64 73 20 6F  |re.1*&v.pounds o|
00001270: 66 20 73 74 72 6F 6E 67  65 72 20 63 6F 70 70 65  |f stronger coppe|
00001280: 72 20 73 6F 6C 75 74 69  6F 6E 00 6C 62 00 6C 62  |r solution.lb.lb|
00001290: 73 00 63 75 2E 00 2E 36  30 00 26 76 2B 32 30 00  |s.cu...60.&v+20.|
000012A0: 63 75 2E 00 2E 36 30 2A  28 26 76 2B 32 30 29 00  |cu...60*(&v+20).|
000012B0: 57 65 61 6B 20 61 6E 64  20 50 75 72 65 20 73 6F  |Weak and Pure so|
000012C0: 6C 75 74 69 6F 6E 73 00  57 65 61 6B 20 61 6D 74  |lutions.Weak amt|
000012D0: 00 50 75 72 65 20 61 6D  74 00 60 34 2B 26 76 20  |.Pure amt.`4+&v |
000012E0: 3D 20 2E 36 28 26 76 2B  32 30 29 27 00 34 2B 26  |= .6(&v+20)'.4+&|
000012F0: 76 3D 2E 36 28 26 76 2B  32 30 29 00 74 68 65 20  |v=.6(&v+20).the |
00001300: 23 20 6F 66 20 70 6F 75  6E 64 73 20 6F 66 20 50  |# of pounds of P|
00001310: 75 72 65 20 63 6F 70 70  65 72 00 32 30 00 48 6F  |ure copper.20.Ho|
00001320: 77 20 6D 75 63 68 20 63  6F 70 70 65 72 20 77 6F  |w much copper wo|
00001330: 75 6C 64 20 62 65 20 6E  65 65 64 65 64 20 74 6F  |uld be needed to|
00001340: 20 63 72 65 61 74 65 20  61 20 62 72 61 73 73 20  | create a brass |
00001350: 74 68 61 74 20 69 73 20  36 30 25 20 63 6F 70 70  |that is 60% copp|
00001360: 65 72 00 70 6F 75 6E 64  73 20 6F 66 20 50 75 72  |er.pounds of Pur|
00001370: 65 20 63 6F 70 70 65 72  00 32 30 00 31 30 00 32  |e copper.20.10.2|
00001380: 30 00 70 6F 75 6E 64 73  20 6F 66 20 36 30 25 20  |0.pounds of 60% |
00001390: 73 6F 6C 75 74 69 6F 6E  00 60 26 76 2B 32 30 27  |solution.`&v+20'|
000013A0: 00 26 76 2B 32 30 20 3D  20 32 30 2B 32 30 20 3D  |.&v+20 = 20+20 =|
000013B0: 20 60 34 30 27 2E 20 54  68 65 72 65 20 61 72 65  | `40'. There are|
000013C0: 20 34 30 20 70 6F 75 6E  64 73 20 6F 66 20 36 30  | 40 pounds of 60|
000013D0: 25 20 63 75 2E 20 73 6F  6C 75 74 69 6F 6E 00 34  |% cu. solution.4|
000013E0: 30 00 63 6F 70 70 65 72  20 69 6E 20 74 68 65 20  |0.copper in the |
000013F0: 50 75 72 65 20 73 6F 6C  75 74 69 6F 6E 00 26 76  |Pure solution.&v|
00001400: 20 3D 20 60 32 30 27 00  31 34 00 32 30 00 61 6D  | = `20'.14.20.am|
00001410: 6F 75 6E 74 20 6F 66 20  63 6F 70 70 65 72 00 2E  |ount of copper..|
00001420: 36 30 28 26 76 2B 32 30  29 20 3D 20 2E 36 30 28  |60(&v+20) = .60(|
00001430: 32 30 2B 32 30 29 20 3D  20 2E 36 30 2A 34 30 20  |20+20) = .60*40 |
00001440: 3D 20 60 32 34 27 00 32  34 00 57 65 61 6B 20 61  |= `24'.24.Weak a|
00001450: 6E 64 20 50 75 72 65 20  73 6F 6C 75 74 69 6F 6E  |nd Pure solution|
00001460: 73 00 40 66 48 6F 77 20  6D 61 6E 79 20 70 6F 75  |s.@fHow many pou|
00001470: 6E 64 73 20 6F 66 20 70  75 72 65 20 73 61 6C 74  |nds of pure salt|
00001480: 20 6D 75 73 74 20 62 65  20 61 64 64 65 64 20 74  | must be added t|
00001490: 6F 20 74 68 65 20 34 30  20 70 6F 75 6E 64 73 20  |o the 40 pounds |
000014A0: 6F 66 20 61 20 35 25 20  73 61 6C 74 20 73 6F 6C  |of a 5% salt sol|
000014B0: 75 74 69 6F 6E 20 69 6E  20 6F 72 64 65 72 20 74  |ution in order t|
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000014E0: 6B 00 50 75 72 65 00 6C  62 73 20 6F 66 20 73 6F  |k.Pure.lbs of so|
000014F0: 6C 2E 00 6C 62 73 20 6F  66 20 73 61 6C 74 00 26  |l..lbs of salt.&|
00001500: 71 34 30 20 70 6F 75 6E  64 73 20 6F 66 20 61 20  |q40 pounds of a |
00001510: 35 25 20 73 61 6C 74 20  73 6F 6C 75 74 69 6F 6E  |5% salt solution|
00001520: 26 71 00 48 6F 77 20 6D  61 6E 79 20 70 6F 75 6E  |&q.How many poun|
00001530: 64 73 20 6F 66 20 50 75  72 65 20 73 61 6C 74 20  |ds of Pure salt |
00001540: 6D 75 73 74 20 62 65 20  61 64 64 65 64 00 70 6F  |must be added.po|
00001550: 75 6E 64 20 6F 66 20 74  68 65 20 57 65 61 6B 20  |und of the Weak |
00001560: 73 61 6C 74 20 73 6F 6C  75 74 69 6F 6E 00 70 6F  |salt solution.po|
00001570: 75 6E 64 20 6F 66 20 74  68 65 20 57 65 61 6B 20  |und of the Weak |
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00001590: 20 60 2E 30 35 27 20 70  6F 75 6E 64 73 00 2E 30  | `.05' pounds..0|
000015A0: 35 00 2E 30 35 00 70 6F  75 6E 64 00 50 75 72 65  |5..05.pound.Pure|
000015B0: 20 73 61 6C 74 20 73 6F  6C 75 74 69 6F 6E 00 70  | salt solution.p|
000015C0: 6F 75 6E 64 20 6F 66 20  74 68 65 20 50 75 72 65  |ound of the Pure|
000015D0: 20 73 61 6C 74 20 73 6F  6C 75 74 69 6F 6E 20 69  | salt solution i|
000015E0: 73 20 27 31 27 70 6F 75  6E 64 00 31 00 31 00 70  |s '1'pound.1.1.p|
000015F0: 6F 75 6E 64 00 70 6F 75  6E 64 00 60 2E 32 34 27  |ound.pound.`.24'|
00001600: 20 70 6F 75 6E 64 73 00  2E 32 34 00 54 68 65 72  | pounds..24.Ther|
00001610: 65 20 61 72 65 20 26 68  34 30 20 70 6F 75 6E 64  |e are &h40 pound|
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00001630: 6F 6C 75 74 69 6F 6E 26  68 00 70 6F 75 6E 64 73  |olution&h.pounds|
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00001650: 74 69 6F 6E 20 65 71 75  61 6C 73 20 60 34 30 27  |tion equals `40'|
00001660: 00 39 00 34 30 00 50 75  72 65 20 73 61 6C 74 00  |.9.40.Pure salt.|
00001670: 70 6F 75 6E 64 73 20 6F  66 20 50 75 72 65 20 73  |pounds of Pure s|
00001680: 61 6C 74 00 60 70 27 20  74 6F 20 72 65 70 72 65  |alt.`p' to repre|
00001690: 73 65 6E 74 20 74 68 65  20 6E 75 6D 62 65 72 20  |sent the number |
000016A0: 6F 66 20 70 6F 75 6E 64  73 20 6F 66 20 50 75 72  |of pounds of Pur|
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000016C0: 00 74 68 65 20 6E 75 6D  62 65 72 20 6F 66 20 70  |.the number of p|
000016D0: 6F 75 6E 64 73 20 6F 66  20 50 75 72 65 20 73 61  |ounds of Pure sa|
000016E0: 6C 74 00 57 65 61 6B 20  61 6E 64 20 50 75 72 65  |lt.Weak and Pure|
000016F0: 20 73 61 6C 74 20 73 6F  6C 75 74 69 6F 6E 73 00  | salt solutions.|
00001700: 60 26 76 2B 34 30 27 20  70 6F 75 6E 64 73 00 26  |`&v+40' pounds.&|
00001710: 76 2B 34 30 00 73 61 6C  74 20 28 69 6E 20 70 6F  |v+40.salt (in po|
00001720: 75 6E 64 73 29 00 70 6F  75 6E 64 73 20 6F 66 20  |unds).pounds of |
00001730: 57 65 61 6B 20 73 6F 6C  75 74 69 6F 6E 00 6C 62  |Weak solution.lb|
00001740: 00 6C 62 73 00 57 65 61  6B 00 2E 30 35 00 34 30  |.lbs.Weak..05.40|
00001750: 00 57 65 61 6B 00 2E 30  35 2A 34 30 00 70 6F 75  |.Weak..05*40.pou|
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00001780: 00 50 75 72 65 00 31 00  26 76 00 50 75 72 65 00  |.Pure.1.&v.Pure.|
00001790: 31 2A 26 76 00 70 6F 75  6E 64 73 20 6F 66 20 73  |1*&v.pounds of s|
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000017C0: 74 00 2E 32 34 00 26 76  2B 34 30 00 73 61 6C 74  |t..24.&v+40.salt|
000017D0: 00 2E 32 34 2A 28 26 76  2B 34 30 29 00 57 65 61  |..24*(&v+40).Wea|
000017E0: 6B 20 61 6E 64 20 50 75  72 65 20 73 6F 6C 75 74  |k and Pure solut|
000017F0: 69 6F 6E 73 00 57 65 61  6B 20 73 61 6C 74 20 61  |ions.Weak salt a|
00001800: 6D 74 00 50 75 72 65 20  73 61 6C 74 20 61 6D 74  |mt.Pure salt amt|
00001810: 00 60 32 2B 26 76 20 3D  20 2E 32 34 28 26 76 2B  |.`2+&v = .24(&v+|
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00001870: 74 20 6D 75 73 74 20 62  65 20 61 64 64 65 64 00  |t must be added.|
00001880: 70 6F 75 6E 64 73 20 6F  66 20 50 75 72 65 20 73  |pounds of Pure s|
00001890: 61 6C 74 00 31 30 00 31  30 00 31 30 00 70 6F 75  |alt.10.10.10.pou|
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000018C0: 3D 20 31 30 2B 34 30 20  3D 20 60 35 30 27 2E 20  |= 10+40 = `50'. |
000018D0: 54 68 65 72 65 20 61 72  65 20 35 30 20 70 6F 75  |There are 50 pou|
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00001910: 00 60 26 76 20 3D 20 31  30 27 00 31 34 00 31 30  |.`&v = 10'.14.10|
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00001930: 2E 32 34 28 26 76 2B 34  30 29 3D 2E 32 34 28 31  |.24(&v+40)=.24(1|
00001940: 30 2B 34 30 29 3D 20 60  31 32 27 2E 20 54 68 65  |0+40)= `12'. The|
00001950: 72 65 20 61 72 65 20 31  32 20 70 6F 75 6E 64 73  |re are 12 pounds|
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00001980: 65 61 6B 20 61 6E 64 20  50 75 72 65 20 73 6F 6C  |eak and Pure sol|
00001990: 75 74 69 6F 6E 73 00 7C  33                       |utions.|3       |
 A@Q{}?@DG09&C(1,{})&C(2,{})&C(3,MIX)&D(
4,UNIT STRNGTH)&D(8,{})&D(12,{})@RREAD@P
READ THE WHOLE PROBLEM. THINK: WHAT ARE 
THE FACTS?  WHAT IS BEING ASKED? (PRESS 
ANY KEY TO CONTINUE.)@HWHAT ARE THE FACT
S? {}@HWHAT IS BEING ASKED? &H{}&H?@I(0)
@RDATA ENTRY@PFILL IN THE GRID -- START 
WITH THE STRENGTHS PER UNIT.@HWHAT IS TH
E STRENGTH PER {}?@HTHE STRENGTH PER {}.
@I(5,I,{})&D(5,{})@HWHAT IS THE STRENGTH
 PER {} OF THE {}?@HTHE STRENGTH PER {}.
@I(6,I,{})&D(6,{})@HWHAT IS THE STRENGTH
 PER {} OF THE MIX?@HTHE STRENGTH PER {}
 OF THE MIX IS {}.@I(7,I,{})@PENTER THE 
FACTS FROM THE PROBLEM INTO THE GRID.@H{
}.@HTHE NUMBER OF {}.@I({},I,{})@PREPRES
ENT THE AMOUNT OF {} TO BE ADDED.@HCHOOS
E A VARIABLE TO REPRESENT THE NUMBER OF 
{}.@HUSE ANY LETTER, SUCH AS {}.@I({},I,
&V)@PREPRESENT THE # OF {} IN THE MIXTUR
E IN TERMS OF "&V" ({}).@HTHE SUM OF THE
 QUANTITIES OF THE {} WILL EQUAL THE QUA
NTITY OF THE MIXTURE.@HTHERE ARE {} IN T
HE MIXTURE.@I(11,I,{})@RPARTS@PWRITE AN 
EXPRESSION TO REPRESENT THE AMOUNT OF {}
 CONTAINED IN EACH SOLUTION.@HMULTIPLY T
HE STRENGTH/UNIT BY THE # OF {}.@HSTRENG
TH/{}  \F13* # OF {} \F24= UNITS OF {} \
N  `{}       \F13*    {}'   \F24= UNITS 
OF {}@I(13,I,{})@HMULTIPLY THE STRENGTH/
UNIT BY THE # OF {}.@HSTRENGTH/{} \F13* 
# OF {} \F24= UNITS OF {} \N `{}        
 \F13*    {}'   \F24= UNITS OF {}@I(14,I
,{})@HMULTIPLY THE STRENGTH/UNIT BY THE 
# OF {}.@HSTRENGTH/{}\F13* # OF {} \F24=
 UNITS OF {} \N   `{}    \F13* ({})' \F2
4= UNITS OF {}@I(15,I,{})  @RWHOLE@PUSE 
THE GRID TO WRITE AN EQUATION TO RELATE 
THE PARTS ({}) TO THE WHOLE (MIX).@H{} +
 ({} AMT) = TOTAL AMT@H{}@I(16,I,{})@S@R
COMPUTE@PSOLVE THE EQUATION FOR "&V" ({}
). USE PENCIL AND PAPER, OR USE THE CALC
ULATOR.@HISOLATE "&V" ON ONE SIDE OF THE
 EQUATION.@HTHE CALCULATOR SOLVES EQUATI
ONS FOR YOU AND DISPLAYS THE STEPS IN TH
E SOLUTION.@I(16,I,&V={})@PNOW FILL IN T
HE ANSWER(S) TO THE PROBLEM. REMEMBER TH
E QUESTION. &Q{}?&Q&W(16)@HTHE NUMBER OF
 {} IS THE VALUE OF "&V".@H&V = `{}'@I({
},I,{}) @S@RCHECK@PREREAD THE PROBLEM. C
HECK YOUR ANSWERS. REPLACE ALL VARIABLES
 IN THE GRID.@HTHE NUMBER OF {} IS THE V
ALUE OF {}.@H{}.@I(11,I,{})@HSUBSTITUTE 
FOR "&V" IN THE EXPRESSION FOR THE AMOUN
T OF {}.@H{}@I({},I,{})@HSUBSTITUTE FOR 
"&V" IN THE EXPRESSION FOR THE {} IN THE
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THE SUM OF {} EQUALS THE TOTAL AMOUNT IN
 THE MIXTURE. ON TO A NEW PROBLEM.)@FA C
AR'S RADIATOR SHOULD CONTAIN 25% ANTIFRE
EZE AND 75% WATER. WHEN TOM CHECKED, THE
 5 GALLONS OF SOLUTION IN HIS RADIATOR W
AS ONLY 10% ANTIFREEZE. HOW MUCH ANTIFRE
EZE MUST BE ADDED.WEAK.PURE.GALS OF SOL.
GALS OF A.F.&QSHOULD CONTAIN 25% ANTIFRE
EZE&Q &Q5 GALLONS OF SOLUTION&Q &QWAS ON
LY 10% ANTIFREEZE&Q.HOW MUCH ANTIFREEZE 
MUST BE ADDED.GALLON OF THE WEAK ANTIFRE
EZE SOLUTION.GALLON OF THE WEAK ANTIFREE
ZE SOLUTION IS `.10' GALLONS..10..10.GAL
LON.PURE ANTIFREEZE SOLUTION.GALLON OF T
HE PURE ANTIFREEZE SOLUTION IS `1' GALLO
N.1.1.GALLON.GALLON..25 GALLONS..25.THE 
5 GALLONS OF SOLUTION IN HIS RADIATOR ON
LY CONTAIN 10% ANTIFREEZE.GALLONS OF 10%
 ANTIFREEZE IS `5'.9.5.PURE ANTIFREEZE.G
ALLONS OF PURE ANTIFREEZE.`P' TO REPRESE
NT THE NUMBER OF GALLONS OF PURE ANTIFRE
EZE.10.GALLONS.THE # OF GALLONS OF PURE 
ANTIFREEZE.10% AND THE PURE ANTIFREEZE S
OLUTIONS.`&V+5' GALLONS.&V+5.ANTIFREEZE.
GALLONS OF WEAK ANTIFREEZE.GL.GLS.WEAK..
10.5.WEAK..10*5.GALLONS OF PURE ANTIFREE
ZE.GL.GLS.PURE.1.&V.PURE.1*&V.GALLONS OF
 PURE SOLUTION.GL.GLS.A.F...25.&V+5.A.F.
..25*(&V+5).WEAK AND PURE SOLUTIONS.WEAK
 AMT.PURE AMT.`.5+&V = .25(&V+5)'..5+&V 
= .25(&V+5).THE # OF GALLONS OF PURE.1.H
OW MUCH ANTIFREEZE MUST BE ADDED.GALLONS
 OF PURE ANTIFREEZE.1.10.1.GALLONS OF 25
% SOLUTION.`&V+5'.&V+5 = 1+5 = `6'. THER
E ARE 6 GALLONS OF 25% SOLUTION.6.ANTIFR
EEZE IN THE PURE SOLUTION.&V = `1'.14.1.
AMOUNT OF ANTIFREEZE..25(&V+5) = .25(1+5
) = `1.5'. THERE ARE 1.5 GALLONS OF ANTI
FREEZE.1.5.WEAK AND PURE SOLUTIONS.@FBRA
SS IS FORMED BY COMBINING MELTED COPPER(
CU.) AND MELTED NICKEL. HOW MUCH COPPER 
WOULD NEED TO BE ADDED TO 20 POUNDS OF B
RASS THAT IS 20% COPPER TO CREATE A BRAS
S THAT IS 60% COPPER.WEAK.PURE.LBS OF BR
ASS.LBS OF CU..&Q20 POUNDS OF BRASS THAT
 IS 20% COPPER&Q.HOW MUCH COPPER WOULD N
EED TO BE ADDED&H.POUND OF THE WEAK COPP
ER SOLUTION.POUND OF THE WEAK COPPER SOL
UTION IS `.20' POUNDS..20..20.POUND.PURE
 COPPER SOLUTION.POUND OF THE PURE COPPE
R SOLUTION IS `1' POUND.1.1.POUND.POUND.
`.60' POUNDS..60.THERE ARE &H20 POUNDS O
F BRASS THAT IS 20% COPPER.POUNDS OF BRA
SS IS `20'.9.20.PURE COPPER.POUNDS OF PU
RE COPPER.`P' TO REPRESENT THE NUMBER OF
 POUNDS OF PURE COPPER.10.POUNDS.THE # O
F POUNDS OF PURE COPPER.20% AND THE PURE
 COPPER SOLUTIONS.`&V+20' POUNDS.&V+20.C
OPPER.POUNDS OF WEAK SOLUTION.LB.LBS.WEA
K..20.20.WEAK..20*20.POUNDS OF PURE SOLU
TION.LB.LBS.PURE.1.&V.PURE.1*&V.POUNDS O
F STRONGER COPPER SOLUTION.LB.LBS.CU...6
0.&V+20.CU...60*(&V+20).WEAK AND PURE SO
LUTIONS.WEAK AMT.PURE AMT.`4+&V = .6(&V+
20)'.4+&V=.6(&V+20).THE # OF POUNDS OF P
URE COPPER.20.HOW MUCH COPPER WOULD BE N
EEDED TO CREATE A BRASS THAT IS 60% COPP
ER.POUNDS OF PURE COPPER.20.10.20.POUNDS
 OF 60% SOLUTION.`&V+20'.&V+20 = 20+20 =
 `40'. THERE ARE 40 POUNDS OF 60% CU. SO
LUTION.40.COPPER IN THE PURE SOLUTION.&V
 = `20'.14.20.AMOUNT OF COPPER..60(&V+20
) = .60(20+20) = .60*40 = `24'.24.WEAK A
ND PURE SOLUTIONS.@FHOW MANY POUNDS OF P
URE SALT MUST BE ADDED TO THE 40 POUNDS 
OF A 5% SALT SOLUTION IN ORDER TO CREATE
 A 24% SALT SOLUTION.WEAK.PURE.LBS OF SO
L..LBS OF SALT.&Q40 POUNDS OF A 5% SALT 
SOLUTION&Q.HOW MANY POUNDS OF PURE SALT 
MUST BE ADDED.POUND OF THE WEAK SALT SOL
UTION.POUND OF THE WEAK SALT SOLUTION IS
 `.05' POUNDS..05..05.POUND.PURE SALT SO
LUTION.POUND OF THE PURE SALT SOLUTION I
S '1'POUND.1.1.POUND.POUND.`.24' POUNDS.
.24.THERE ARE &H40 POUNDS OF A 5% SALT S
OLUTION&H.POUNDS OF 5% SALT SOLUTION EQU
ALS `40'.9.40.PURE SALT.POUNDS OF PURE S
ALT.`P' TO REPRESENT THE NUMBER OF POUND
S OF PURE SALT.10.POUNDS.THE NUMBER OF P
OUNDS OF PURE SALT.WEAK AND PURE SALT SO
LUTIONS.`&V+40' POUNDS.&V+40.SALT (IN PO
UNDS).POUNDS OF WEAK SOLUTION.LB.LBS.WEA
K..05.40.WEAK..05*40.POUNDS OF PURE SALT
 SOLUTION.LB.LBS.PURE.1.&V.PURE.1*&V.POU
NDS OF STRONGER SALT SOLUTION.LB.LBS.SAL
T..24.&V+40.SALT..24*(&V+40).WEAK AND PU
RE SOLUTIONS.WEAK SALT AMT.PURE SALT AMT
.`2+&V = .24(&V+40)'.2+&V=.24(&V+40).THE
 # OF POUNDS OF PURE SALT.10.HOW MANY PO
UNDS OF PURE SALT MUST BE ADDED.POUNDS O
F PURE SALT.10.10.10.POUNDS OF 24% SOLUT
ION.&V+40.&V+40 = 10+40 = `50'. THERE AR
E 50 POUNDS OF 24% SOLUTION.50.SALT IN T
HE PURE SOLUTION.`&V = 10'.14.10.AMOUNT 
OF SALT..24(&V+40)=.24(10+40)= `12'. THE
RE ARE 12 POUNDS OF SALT IN THE MIXTURE.
12.THE WEAK AND PURE SOLUTIONS.|3
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