DIST5L3
FILE INFORMATION
FILENAME(S): DIST5L3
FILE TYPE(S): PRG
FILE SIZE: 5.6K
FIRST SEEN: 2025-10-19 22:48:55
APPEARS ON: 1 disk(s)
FILE HASH
58c8f2cab452319d4284a1cee3cc4bd7856de583a37f932dfd9dbcccafef06ad
FOUND ON DISKS (1 DISKS)
| DISK TITLE | FILENAME | FILE TYPE | COLLECTION | TRACK | SECTOR | ACTIONS |
|---|---|---|---|---|---|---|
| HHM 100785 43S1 | DIST5L3 | PRG | Radd Maxx | 27 | 0 | DOWNLOAD FILE |
FILE CONTENT & ANALYSIS
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00000EE0: 00 62 00 76 00 62 00 76 00 62 00 35 30 28 26 76 |.b.v.b.v.b.50(&v|
00000EF0: 2B 2E 35 29 00 76 00 35 35 26 76 00 54 68 65 20 |+.5).v.55&v.The |
00000F00: 42 75 73 27 20 44 69 73 74 61 6E 63 65 20 3D 20 |Bus' Distance = |
00000F10: 54 68 65 20 56 61 6E 27 73 20 44 69 73 74 61 6E |The Van's Distan|
00000F20: 63 65 20 5C 6E 20 20 20 20 60 35 30 28 26 76 2B |ce \n `50(&v+|
00000F30: 2E 35 29 20 20 20 20 20 5C 66 32 30 3D 20 20 35 |.5) \f20= 5|
00000F40: 35 26 76 27 00 35 30 28 26 76 2B 2E 35 29 3D 35 |5&v'.50(&v+.5)=5|
00000F50: 35 26 76 00 35 00 41 66 74 65 72 20 68 6F 77 20 |5&v.5.After how |
00000F60: 6D 75 63 68 20 74 69 6D 65 20 77 69 6C 6C 20 69 |much time will i|
00000F70: 74 20 63 61 74 63 68 20 75 70 20 74 6F 20 74 68 |t catch up to th|
00000F80: 65 20 62 75 73 3F 00 74 68 65 20 76 61 6E 00 76 |e bus?.the van.v|
00000F90: 61 6E 00 35 00 35 00 35 00 74 68 65 20 62 75 73 |an.5.5.5.the bus|
00000FA0: 27 00 26 76 20 3D 20 35 2C 20 61 6E 64 20 26 76 |'.&v = 5, and &v|
00000FB0: 2B 2E 35 20 72 65 70 72 65 73 65 6E 74 73 20 74 |+.5 represents t|
00000FC0: 68 65 20 62 75 73 27 20 74 69 6D 65 2C 20 73 6F |he bus' time, so|
00000FD0: 20 74 68 65 20 62 75 73 20 74 72 61 76 65 6C 6C | the bus travell|
00000FE0: 65 64 20 66 6F 72 20 60 35 2E 35 27 20 68 6F 75 |ed for `5.5' hou|
00000FF0: 72 73 2E 00 31 30 00 35 2E 35 00 74 68 65 20 62 |rs..10.5.5.the b|
00001000: 75 73 27 00 26 76 3D 35 20 61 6E 64 20 35 30 28 |us'.&v=5 and 50(|
00001010: 26 76 2B 2E 35 29 20 72 65 70 72 65 73 65 6E 74 |&v+.5) represent|
00001020: 73 20 74 68 65 20 62 75 73 27 20 64 69 73 74 61 |s the bus' dista|
00001030: 6E 63 65 2C 20 73 6F 20 35 30 20 2A 20 35 2E 35 |nce, so 50 * 5.5|
00001040: 20 6F 72 20 60 32 37 35 27 20 3D 20 74 68 65 20 | or `275' = the |
00001050: 62 75 73 27 20 64 69 73 74 61 6E 63 65 2E 00 32 |bus' distance..2|
00001060: 37 35 00 74 68 65 20 76 61 6E 27 73 00 26 76 3D |75.the van's.&v=|
00001070: 35 20 61 6E 64 20 35 35 26 76 20 72 65 70 72 65 |5 and 55&v repre|
00001080: 73 65 6E 74 73 20 74 68 65 20 76 61 6E 27 73 20 |sents the van's |
00001090: 64 69 73 74 61 6E 63 65 2C 20 73 6F 20 35 35 20 |distance, so 55 |
000010A0: 2A 20 35 2C 20 6F 72 20 60 32 37 35 27 20 3D 20 |* 5, or `275' = |
000010B0: 74 68 65 20 76 61 6E 27 73 20 64 69 73 74 61 6E |the van's distan|
000010C0: 63 65 2E 00 32 37 35 00 54 68 65 20 62 75 73 27 |ce..275.The bus'|
000010D0: 00 74 68 65 20 76 61 6E 27 73 00 40 66 42 6F 62 |.the van's.@fBob|
000010E0: 20 63 79 63 6C 65 73 20 61 74 20 61 20 72 61 74 | cycles at a rat|
000010F0: 65 20 6F 66 20 32 34 20 6B 6D 2F 68 72 20 61 6E |e of 24 km/hr an|
00001100: 64 20 47 72 65 67 20 63 79 63 6C 65 73 20 61 74 |d Greg cycles at|
00001110: 20 33 30 20 6B 6D 2F 68 72 2E 20 49 66 20 47 72 | 30 km/hr. If Gr|
00001120: 65 67 20 67 69 76 65 73 20 42 6F 62 20 61 20 31 |eg gives Bob a 1|
00001130: 35 20 6D 69 6E 75 74 65 20 68 65 61 64 20 73 74 |5 minute head st|
00001140: 61 72 74 2C 20 68 6F 77 20 6C 6F 6E 67 20 77 69 |art, how long wi|
00001150: 6C 6C 20 68 65 20 68 61 76 65 20 74 6F 20 72 69 |ll he have to ri|
00001160: 64 65 20 62 65 66 6F 72 65 20 68 65 20 63 61 74 |de before he cat|
00001170: 63 68 65 73 20 75 70 20 74 6F 20 42 6F 62 3F 00 |ches up to Bob?.|
00001180: 42 6F 62 00 47 72 65 67 00 42 6F 62 20 61 6E 64 |Bob.Greg.Bob and|
00001190: 20 47 72 65 67 20 63 79 63 6C 65 20 74 68 65 20 | Greg cycle the |
000011A0: 73 61 6D 65 20 64 69 73 74 61 6E 63 65 2C 20 62 |same distance, b|
000011B0: 75 74 20 42 6F 62 20 74 61 6B 65 73 20 31 35 20 |ut Bob takes 15 |
000011C0: 6D 69 6E 75 74 65 73 20 6C 6F 6E 67 65 72 20 74 |minutes longer t|
000011D0: 68 61 6E 20 47 72 65 67 00 26 68 48 6F 77 20 6C |han Greg.&hHow l|
000011E0: 6F 6E 67 20 77 69 6C 6C 20 68 65 20 68 61 76 65 |ong will he have|
000011F0: 20 74 6F 20 72 69 64 65 20 62 65 66 6F 72 65 20 | to ride before |
00001200: 68 65 20 63 61 74 63 68 65 73 20 75 70 20 74 6F |he catches up to|
00001210: 20 42 6F 62 3F 26 68 00 62 00 42 6F 62 27 73 00 | Bob?&h.b.Bob's.|
00001220: 67 00 47 72 65 67 27 73 00 62 00 67 00 54 68 65 |g.Greg's.b.g.The|
00001230: 20 62 6F 79 73 00 63 79 63 6C 65 00 62 00 67 00 | boys.cycle.b.g.|
00001240: 54 68 65 79 00 72 69 64 65 00 62 3D 44 67 00 54 |They.ride.b=Dg.T|
00001250: 68 65 20 62 6F 79 73 00 62 00 67 00 42 6F 62 27 |he boys.b.g.Bob'|
00001260: 73 20 66 69 6E 61 6C 00 47 72 65 67 27 73 20 66 |s final.Greg's f|
00001270: 69 6E 61 6C 00 6B 69 6C 6F 6D 65 74 65 72 73 20 |inal.kilometers |
00001280: 70 65 72 20 68 6F 75 72 20 28 60 6B 6D 2F 68 72 |per hour (`km/hr|
00001290: 27 29 00 34 00 6B 6D 2F 68 72 00 68 6F 75 72 73 |').4.km/hr.hours|
000012A0: 20 28 60 68 72 27 29 00 32 00 68 72 00 6B 69 6C | (`hr').2.hr.kil|
000012B0: 6F 6D 65 74 65 72 73 20 28 60 6B 6D 27 29 00 32 |ometers (`km').2|
000012C0: 00 6B 6D 00 26 68 42 6F 62 20 63 79 63 6C 65 73 |.km.&hBob cycles|
000012D0: 20 61 74 20 61 20 72 61 74 65 20 6F 66 20 32 34 | at a rate of 24|
000012E0: 20 6B 6D 2F 68 72 26 68 2E 00 42 6F 62 27 73 20 | km/hr&h..Bob's |
000012F0: 72 61 74 65 20 69 73 20 60 32 34 27 20 6B 6D 2F |rate is `24' km/|
00001300: 68 72 2E 00 32 34 00 26 68 47 72 65 67 20 63 79 |hr..24.&hGreg cy|
00001310: 63 6C 65 73 20 61 74 20 61 20 72 61 74 65 20 6F |cles at a rate o|
00001320: 66 20 33 30 20 6B 6D 2F 68 72 26 68 2E 00 47 72 |f 30 km/hr&h..Gr|
00001330: 65 67 27 73 20 72 61 74 65 20 69 73 20 60 33 30 |eg's rate is `30|
00001340: 27 20 6B 6D 2F 68 72 2E 00 33 30 00 62 6F 79 20 |' km/hr..30.boy |
00001350: 63 79 63 6C 65 64 00 47 72 65 67 20 72 69 64 65 |cycled.Greg ride|
00001360: 73 20 66 6F 72 00 42 6F 62 00 67 00 68 6F 75 72 |s for.Bob.g.hour|
00001370: 73 20 47 72 65 67 20 72 6F 64 65 00 31 31 00 42 |s Greg rode.11.B|
00001380: 6F 62 20 63 79 63 6C 65 64 00 47 72 65 67 27 73 |ob cycled.Greg's|
00001390: 20 74 69 6D 65 20 28 63 6F 6E 76 65 72 74 20 74 | time (convert t|
000013A0: 68 65 20 61 6E 73 77 65 72 20 74 6F 20 68 6F 75 |he answer to hou|
000013B0: 72 73 29 00 42 6F 62 20 73 74 61 72 74 65 64 20 |rs).Bob started |
000013C0: 31 35 20 6D 69 6E 75 74 65 73 2C 20 6F 72 20 2E |15 minutes, or .|
000013D0: 32 35 20 68 6F 75 72 73 20 62 65 66 6F 72 65 20 |25 hours before |
000013E0: 47 72 65 67 2C 20 73 6F 20 42 6F 62 27 73 20 74 |Greg, so Bob's t|
000013F0: 69 6D 65 20 69 73 20 60 26 76 2B 2E 32 35 27 20 |ime is `&v+.25' |
00001400: 68 6F 75 72 73 2E 00 31 30 00 26 76 2B 2E 32 35 |hours..10.&v+.25|
00001410: 00 60 32 34 20 20 5C 66 30 36 2A 20 28 26 76 2B |.`24 \f06* (&v+|
00001420: 2E 32 35 29 27 20 5C 66 31 35 3D 20 42 6F 62 27 |.25)' \f15= Bob'|
00001430: 73 00 32 34 28 26 76 2B 2E 32 35 29 00 60 33 30 |s.24(&v+.25).`30|
00001440: 20 5C 66 30 36 2A 20 20 26 76 27 20 5C 66 31 35 | \f06* &v' \f15|
00001450: 3D 20 47 72 65 67 27 73 20 44 69 73 74 2E 00 33 |= Greg's Dist..3|
00001460: 30 26 76 00 62 00 67 00 62 00 67 00 62 00 32 34 |0&v.b.g.b.g.b.24|
00001470: 28 26 76 2B 2E 32 35 29 00 67 00 33 30 26 76 00 |(&v+.25).g.30&v.|
00001480: 42 6F 62 27 73 20 44 69 73 74 61 6E 63 65 20 5C |Bob's Distance \|
00001490: 66 31 38 3D 20 47 72 65 67 27 73 20 44 69 73 74 |f18= Greg's Dist|
000014A0: 61 6E 63 65 20 5C 6E 20 20 20 20 60 32 34 28 26 |ance \n `24(&|
000014B0: 76 2B 2E 32 35 29 20 5C 66 31 38 3D 20 20 20 20 |v+.25) \f18= |
000014C0: 20 33 30 26 76 27 00 32 34 28 26 76 2B 2E 32 35 | 30&v'.24(&v+.25|
000014D0: 29 3D 33 30 26 76 00 31 00 48 6F 77 20 6C 6F 6E |)=30&v.1.How lon|
000014E0: 67 20 77 69 6C 6C 20 68 65 20 68 61 76 65 20 74 |g will he have t|
000014F0: 6F 20 72 69 64 65 20 62 65 66 6F 72 65 20 68 65 |o ride before he|
00001500: 20 63 61 74 63 68 65 73 20 75 70 20 74 6F 20 42 | catches up to B|
00001510: 6F 62 3F 00 47 72 65 67 00 47 72 65 67 00 31 00 |ob?.Greg.Greg.1.|
00001520: 31 00 31 00 42 6F 62 27 73 00 26 76 3D 31 20 61 |1.1.Bob's.&v=1 a|
00001530: 6E 64 20 26 76 2B 2E 32 35 20 72 65 70 72 65 73 |nd &v+.25 repres|
00001540: 65 6E 74 73 20 42 6F 62 27 73 20 74 69 6D 65 2C |ents Bob's time,|
00001550: 20 73 6F 20 31 2B 2E 32 35 2C 20 6F 72 20 60 31 | so 1+.25, or `1|
00001560: 2E 32 35 27 20 69 73 20 42 6F 62 27 73 20 74 69 |.25' is Bob's ti|
00001570: 6D 65 2E 00 31 30 00 31 2E 32 35 00 42 6F 62 27 |me..10.1.25.Bob'|
00001580: 73 00 26 76 3D 31 20 61 6E 64 20 32 34 28 26 76 |s.&v=1 and 24(&v|
00001590: 2B 2E 32 35 29 20 72 65 70 72 65 73 65 6E 74 73 |+.25) represents|
000015A0: 20 42 6F 62 27 73 20 64 69 73 74 61 6E 63 65 2C | Bob's distance,|
000015B0: 20 73 6F 20 32 34 20 2A 20 31 2E 32 35 2C 20 6F | so 24 * 1.25, o|
000015C0: 72 20 60 33 30 27 20 69 73 20 42 6F 62 27 73 20 |r `30' is Bob's |
000015D0: 64 69 73 74 61 6E 63 65 2E 00 33 30 00 47 72 65 |distance..30.Gre|
000015E0: 67 27 73 00 26 76 3D 31 20 61 6E 64 20 33 30 26 |g's.&v=1 and 30&|
000015F0: 76 20 72 65 70 72 65 73 65 6E 74 73 20 47 72 65 |v represents Gre|
00001600: 67 27 73 20 64 69 73 74 61 6E 63 65 2C 20 73 6F |g's distance, so|
00001610: 20 60 33 30 27 20 69 73 20 47 72 65 67 27 73 20 | `30' is Greg's |
00001620: 64 69 73 74 61 6E 63 65 2E 00 33 30 00 42 6F 62 |distance..30.Bob|
00001630: 27 73 00 47 72 65 67 27 73 00 7C 2E |'s.Greg's.|. |
A/ @Q{}@DG05&D(1,UNIT/MEAS)&C(2
,{})&C(3,{})&D(4,RATE)&D(8,TIME)&D(12,DI
ST.)@RREAD@PREAD THE WHOLE PROBLEM. THIN
K: WHAT ARE THE FACTS? WHAT IS BEING AS
KED? (PRESS ANY KEY TO CONTINUE).@HWHAT
ARE THE FACTS? {}.@HWHAT IS BEING ASKED
? {}@I(0)@RPLAN @PLET D{} = {} DISTANCE
AND D{} = {} DISTANCE. WRITE AN EQUATION
THAT RELATES D{} TO D{}.@H{} BOTH {} TH
E SAME DISTANCE.@H`D{} = D{}' SHOWS THAT
{} BOTH {} THE SAME DISTANCE.@I(16,C0,
)@PONE ANSWER IS `D{}'. CHANGE YOUR ANSW
ER IF IT IS NOT EQUIVALENT. (PRESS RETUR
N)@H{} BOTH TRAVEL THE SAME DISTANCE.@H`
D{}=D{}' SHOWS THAT {} DISTANCE IS EQUAL
TO {} DISTANCE.@I(16,C0, )@RDATA ENTRY@
PFILL IN THE UNITS BY WHICH RATE, TIME A
ND DISTANCE ARE MEASURED. (USE ABBREVIAT
ED FORM.)@HRATE IS COMMONLY MEASURED IN
MILES PER HOUR(MI/HR), FEET PER SECOND (
FT/SEC), METERS PER KILOMETER (M/KM), ET
C.@HTHE RATE OF SPEED IN THIS PROBLEM IS
MEASURED IN {}.@I(5,C{},{})@HTIME IS CO
MMONLY MEASURED IN SECONDS (SEC), MINUTE
S (MIN), HOURS (HR), DAYS (DA), ETC.@HTI
ME IN THIS PROBLEM IS MEASURED IN {}.@I(
9,C{},{})@HDISTANCE IS COMMONLY MEASURED
IN FEET (FT), YARDS (YD), MILES (MI), M
ETERS (M), KILOMETERS (KM), ETC.@HDISTAN
CE IN THIS PROBLEM IS MEASURED IN {}.@I(
13,C{},{})@PENTER THE FACTS FROM THE PRO
BLEM INTO THE GRID.@H{}@H{}@I(6,I,{})@H{
}@H{}@I(7,I,{})@PREPRESENT THE TIME EACH
{}.@HUSE A VARIABLE TO REPRESENT THE SM
ALLER AMOUNT OF TIME. IN THIS CASE, {} L
ESS TIME THAN {}.@HUSE A VARIABLE, SUCH
AS `{}' TO REPRESENT THE NUMBER OF {}.@I
({},I,&V)@HREPRESENT THE TIME {} IN TERM
S OF "&V", {}.@H{}@I({},I,{})@RPARTS@PWR
ITE AN EXPRESSION TO REPRESENT TBE DISTA
NCE TRAVELLED BY EACH VEHICLE.@HRATE*TIM
E = DISTANCE@HRATE \F06* TIME \F15= DI
STANCE \N{}@I(14,I,{})@HRATE*TIME = DIST
ANCE@HRATE \F06* TIME \F15= DISTANCE \N{
}@I(15,I,{})@RWHOLE&D(16, )@PSUBSTITUTE
YOUR EXPRESSIONS FOR D{} AND D{} IN THE
EQUATION : D{} = D{}@HD{} = {} AND D{} =
{}.@H{}@I(16,I,{})@S@RCOMPUTE@PSOLVE TH
E EQUATION FOR "&V". USE PAPER AND PENCI
L AND ENTER THE FINAL EQUATIONS OR USE T
HE CALCULATOR.@HISOLATE "&V" ON ONE SIDE
OF THE EQUATION.@HTHE CALCULATOR SOLVES
EQUATIONS FOR YOU AND DISPLAYS THE STEP
S IN THE SOLUTION.@I(16,I,&V={})@PENTER
YOUR ANSWER TO THE PROBLEM IN THE GRID.
REMEMBER THE QUESTION. &Q{}&Q&W(16)@HTHE
TIME FOR {} IS THE VALUE OF "&V".@HTHE
TIME FOR {} IS THE VALUE OF "&V". &V = {
}, SO ENTER '{}'.@I(11,I,{})@S@RCHECK@PR
EREAD THE PROBLEM. CHECK YOUR ANSWERS. E
VALUATE THE REMAINING EXPRESSIONS IN THE
CHART.@HSUBSTITUTE FOR "&V" IN THE EXPR
ESSION FOR {} TIME. THEN CALCULATE THE R
ESULT.@H{}@I({},I,{})@HSUBSTITUTE FOR "&
V" IN THE EXPRESSION FOR {} DISTANCE. TH
EN CALCULATE THE RESULT.@H{}@I(14,I,{})@
HSUBSTITUTE FOR "&V" IN THE EXPRESSION F
OR {} DISTANCE. THEN CALCULATE THE RESUL
T.@H{}@I(15,I,{})&D(0,CHECK YOUR WORK. {
} DISTANCE SHOULD EQUAL {} DISTANCE. (ON
TO A NEW PROBLEM.))@FAT 1 PM, A BUS LEA
VES AMARILLO FOR EL PASO AT 50 KM/HR. IF
AN EXPRESS VAN TRAVELLING AT 55 KM/HR L
EAVES FOR THE SAME TRIP AT 1:30 PM, HOW
LONG WILL IT TAKE THE VAN TO PASS THE BU
S?.BUS.VAN.THE BUS AND THE VAN WILL TRAV
EL THE SAME DISTANCE, BUT THE BUS TAKES
1/2 HOUR LONGER.HOW LONG WILL IT TAKE TH
E VAN TO PASS THE BUS?.B.THE BUS'.V.THE
VAN'S.B.V.THE BUS AND THE VAN.DRIVE.B.V.
THE BUS AND THE VAN.DRIVE.B=DV.THE BUS A
ND THE VAN.B.V.THE BUS'.THE VAN'S.KILOME
TERS PER HOUR (`KM/HR').4.KM/HR.HOURS (`
HR').2.HR.KILOMETERS (`KM').2.KM.THE BUS
TRAVELS AT &H50 KM/HR&H..THE RATE FOR T
HE BUS IS `50' KM/HR..50.THE VAN TRAVELS
AT &H55 KM/HR&H..THE RATE FOR THE VAN I
S `55' KM/HR..55.VEHICLE TRAVELS.THE VAN
TRAVELS FOR.THE BUS.V.HOURS THE VAN TRA
VELS.11.THE BUS TRAVELS.THE TIME THE VAN
TRAVELS.SINCE THE BUS STARTED AT 1 PM A
ND THE VAN STARTED AT 1:30 PM, THE BUS T
AKES 1/2 HOUR LONGER, OR `&V+.5' HOURS..
10.&V+.5. `50 \F06* (&V+.5)' \F15= BUS'.
50(&V+.5). `55 \F06* &V' \F15= VAN'S DI
ST..55&V.B.V.B.V.B.50(&V+.5).V.55&V.THE
BUS' DISTANCE = THE VAN'S DISTANCE \N
`50(&V+.5) \F20= 55&V'.50(&V+.5)=5
5&V.5.AFTER HOW MUCH TIME WILL IT CATCH
UP TO THE BUS?.THE VAN.VAN.5.5.5.THE BUS
'.&V = 5, AND &V+.5 REPRESENTS THE BUS'
TIME, SO THE BUS TRAVELLED FOR `5.5' HOU
RS..10.5.5.THE BUS'.&V=5 AND 50(&V+.5) R
EPRESENTS THE BUS' DISTANCE, SO 50 * 5.5
OR `275' = THE BUS' DISTANCE..275.THE V
AN'S.&V=5 AND 55&V REPRESENTS THE VAN'S
DISTANCE, SO 55 * 5, OR `275' = THE VAN'
S DISTANCE..275.THE BUS'.THE VAN'S.@FBOB
CYCLES AT A RATE OF 24 KM/HR AND GREG C
YCLES AT 30 KM/HR. IF GREG GIVES BOB A 1
5 MINUTE HEAD START, HOW LONG WILL HE HA
VE TO RIDE BEFORE HE CATCHES UP TO BOB?.
BOB.GREG.BOB AND GREG CYCLE THE SAME DIS
TANCE, BUT BOB TAKES 15 MINUTES LONGER T
HAN GREG.&HHOW LONG WILL HE HAVE TO RIDE
BEFORE HE CATCHES UP TO BOB?&H.B.BOB'S.
G.GREG'S.B.G.THE BOYS.CYCLE.B.G.THEY.RID
E.B=DG.THE BOYS.B.G.BOB'S FINAL.GREG'S F
INAL.KILOMETERS PER HOUR (`KM/HR').4.KM/
HR.HOURS (`HR').2.HR.KILOMETERS (`KM').2
.KM.&HBOB CYCLES AT A RATE OF 24 KM/HR&H
..BOB'S RATE IS `24' KM/HR..24.&HGREG CY
CLES AT A RATE OF 30 KM/HR&H..GREG'S RAT
E IS `30' KM/HR..30.BOY CYCLED.GREG RIDE
S FOR.BOB.G.HOURS GREG RODE.11.BOB CYCLE
D.GREG'S TIME (CONVERT THE ANSWER TO HOU
RS).BOB STARTED 15 MINUTES, OR .25 HOURS
BEFORE GREG, SO BOB'S TIME IS `&V+.25'
HOURS..10.&V+.25.`24 \F06* (&V+.25)' \F
15= BOB'S.24(&V+.25).`30 \F06* &V' \F15
= GREG'S DIST..30&V.B.G.B.G.B.24(&V+.25)
.G.30&V.BOB'S DISTANCE \F18= GREG'S DIST
ANCE \N `24(&V+.25) \F18= 30&V'.2
4(&V+.25)=30&V.1.HOW LONG WILL HE HAVE T
O RIDE BEFORE HE CATCHES UP TO BOB?.GREG
.GREG.1.1.1.BOB'S.&V=1 AND &V+.25 REPRES
ENTS BOB'S TIME, SO 1+.25, OR `1.25' IS
BOB'S TIME..10.1.25.BOB'S.&V=1 AND 24(&V
+.25) REPRESENTS BOB'S DISTANCE, SO 24 *
1.25, OR `30' IS BOB'S DISTANCE..30.GRE
G'S.&V=1 AND 30&V REPRESENTS GREG'S DIST
ANCE, SO `30' IS GREG'S DISTANCE..30.BOB
'S.GREG'S.|.
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