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00000EC0: 20 54 4F 20 43 4F 4E 54 49 4E 55 45 22 00 E3 12 | TO CONTINUE"...|
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00000EE0: 36 37 30 00 F2 12 90 06 99 C7 28 31 34 37 29 3B |670.......(147);|
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....D.. LOCKEY : HUNTINGTON 2.C.N.. FIT
TO PET BY EMOND & GAMBLE 80.Z.X.. COLUMB
IA COLLEGE.Z.... 1619 W10 AVE VANCOUVER
BC......59468,12......G(147):.:.:.:..15)
".LOCKEY":.:.... .."A COMPETITIVE INHIBI
TION STUDY OF THE ENZYME ";......"ACET
YLCHOLINESTERASE FEATURING THE LOCK AN
D KEY HYPOTHESIS.":.:..W....:."DO YOU WA
NT INSTRUCTIONS (Y/N)";.`.... N$.Q.H..N$
."N". 540...R..N$.."Y".190......G(147);.
M....:." YOU ARE CONDUCTING AN INVESTIGA
TION OF THE ENZYME ";......"ACETYLCHOLIN
ESTERASE. FROM THE NAME YOU CAN TELL";
.J...."THAT THIS ENZYME WORKS ON THE C
HEMICAL ACETYLCHOLINE - ";......"IT BREA
KS ACETYLCHOLINE INTO ACETIC ACID AND C
HOLINE.".G....:." WE WANT TO INVESTIGATE
WHICH INHIBITOR IS THE MOST ";......"EF
FECTIVE IN SLOWING THE NORMAL ACTION
OF THE ENZYME."..."...K.,.."THIS WILL GI
VE US VALUABLE INFORMATION ON ITS ACTIO
N.".U.6..1660...@..:." THE CODE F
OR THE INHIBITOR IS:"...J..:."
1 = AMMONIUM".L.T.." 2 = DI
METHYLAMINE"...^.." 3 = METHY
LAMINE "...H.." 4 = PROSTIGM
INE ".;.R.." 5 = TRIMETHYLAMI
NE"._.|.." 0 = NO INHIBITOR".
.....:." IN THIS STUDY YOU CAN CONTROL:"
:......." THE AMOUNT OF ACETYLCHOL
INE".X...." THE TYPE OF INHIBITOR"
......" AND THE AMOUNT OF INHIBITO
R".H....:."BY COMPARING THE STRUCTURE OF
ACETYLCHOLINE WITH ";......"T
HE STRUCTURE OF THE FIVE INHIBITORS YOU
SHOULD ";...B.."BE ABLE TO MAKE AN HYP
OTHESIS AS TO WHICH OF THE ";...L.." FI
VE INHIBITORS WILL BE THE MOST EF
FECTIVE."...V..1660.:....:." REMEMBER:
INCLUDE YOUR KNOWLEDGE OF THE";.M....
" LOCK AND KEY MODEL OF ENZYME ACT
ION."......:.".BE SURE TO CONSULT THE IM
PORTANT ".M....".STRUCTURAL FORMULA
E LISTED IN THE "......". INF
ORMATION PACKET. "............
N.1...&...'.0.. T,P1,C,K1,M,X,V.C.:..0,0
,0,9E-5,3E-3,1000,0.S.D.."**************
**************************".}.N..T1.0...
X..:."AMOUNT OF ACETYLCHOLINE - FROM 0 T
O 3 MILLIMOLES";.C.B.. S1.R.L.. S1.3.6
00...V.. S1.0.600...... S1.0.680.!....:.
".NO REACTION IS POSSIBLE WITHOUT
".7.....15)".SUBSTRATE".G....: K . 1410.
X.... S1.S1.1000.C....S2.S1......"TYPE O
F INHIBITOR - USE CODE FROM 0 TO 5";...F
..K2...P..K2...(K2).700...Z..K2.5.700.K.
...K2.0.700.Z....K2.0.1000......K2.4.850
......K2.4.820............... ..K2.2.6E.
3...*..950. .4.../.>..K2.1.6E.5.8.H..950
.G.R..K2..2.890.M.\...X.F..K2..9.A.P..95
0.O.Z..K2.2.930.U..........K2..12......9
50............K2.2.1E.2.I...."AMOUNT OF
INHIBITOR IN MILLIMOLES";.P....I...J..I.
I.1000...T..I.0.950......I..0.1020.....K
2.1......I.0. ....K.K1.(K1.I.K2).L...."D
ATA FORMAT: TABLE OR GRAPH (T/G)";N$.R..
...X.....^.$...D.....U.8..N$."T".1230...
B.K .1570...L..N$."G".1600...V..1280...`
..T1.X.1330...J..T.T1.1.T1.50.C.T...Y.~.
.V1.(M.S1).(S1.K)......V.(V.V1).1000....
..S1.S1.V......P1.P1.V......V.V1......T.
%....T1.T1.50./.D..1100.5.N...;.X...K...
."MINS ACETYLCHOLINE TOTAL ACET
IC"......".ELAPSED REMAINING AC
ID PRODUCED".M...."........ .........
............."......(T1).500.15).
(S1.10.5..5).100.30).(P1.10.5..5).100.$.
....(S1.10.5..5).100..0.1310......1120.[
....: ."THE REACTION HAS RUN TO COMPLETI
ON".E.(..1390...2.."DO YOU WANT TO CONTI
NUE THE ASSAY (Y/N)";A$...<.....F..A$."N
".1390...P..A$.."Y".1330.M.Z..X.X.500.W.
D..1130...N.....X.."CONCENTRATION OF INH
IBITOR REMAINING:"I.1000;"MILLIMOLES".#.
....F...."ANOTHER EXPERIMENT (Y/N)";E$.L
.....]. ..E$."Y".1540.O....E$.."N".1420.
U.....{.......H.....R...................
...................N.N.1......550.O."..:
FA.27.(S1.1000)...,.."MIN. MILLIMOLES
ACETIC ACID PRODUCED"...6..".... ....
.............................".>.@..T1.5
00.5);.\.J.XX.(.(P1.10.5..5).100).FA.Q.T
..XX.0.."0":.1640...^..II.1.XX:.".";:.:.
.(P1.10.5..5).100...H..1290...R...M.|..:
.".PRESS ANY KEY TO CONTINUE"......ZZ$:.
ZZ$."".1670......G(147);:....
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