DIST3L4
FILE INFORMATION
FILENAME(S): DIST3L4
FILE TYPE(S): PRG
FILE SIZE: 7K
FIRST SEEN: 2025-10-19 22:48:55
APPEARS ON: 1 disk(s)
FILE HASH
85ad6fdf34740e5ff731fdf1f615f80b58f7862c7105a74a5a5a9671ae87f253
FOUND ON DISKS (1 DISKS)
| DISK TITLE | FILENAME | FILE TYPE | COLLECTION | TRACK | SECTOR | ACTIONS |
|---|---|---|---|---|---|---|
| HHM 100785 43S1 | DIST3L4 | PRG | Radd Maxx | 8 | 0 | DOWNLOAD FILE |
FILE CONTENT & ANALYSIS
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00000C40: 40 66 42 72 69 61 6E 20 64 72 69 76 65 73 20 35 |@fBrian drives 5|
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00000CF0: 44 61 76 65 00 42 72 69 61 6E 00 54 68 65 79 20 |Dave.Brian.They |
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00000D30: 75 6E 74 69 6C 20 74 68 65 79 20 77 65 72 65 20 |until they were |
00000D40: 32 36 32 2E 35 20 6D 69 20 61 70 61 72 74 2E 00 |262.5 mi apart..|
00000D50: 48 6F 77 20 66 61 73 74 20 64 69 64 20 65 61 63 |How fast did eac|
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00000DF0: 76 65 20 64 72 6F 76 65 20 66 6F 72 20 26 68 33 |ve drove for &h3|
00000E00: 2E 35 20 68 6F 75 72 73 26 68 2E 00 44 61 76 65 |.5 hours&h..Dave|
00000E10: 20 77 61 73 20 60 33 2E 35 27 20 68 6F 75 72 73 | was `3.5' hours|
00000E20: 2E 00 33 2E 35 00 42 72 69 61 6E 27 73 20 74 69 |..3.5.Brian's ti|
00000E30: 6D 65 20 69 73 20 74 68 65 20 73 61 6D 65 20 61 |me is the same a|
00000E40: 73 20 44 61 76 65 27 73 2E 00 42 72 69 61 6E 20 |s Dave's..Brian |
00000E50: 77 61 73 20 60 33 2E 35 27 20 68 6F 75 72 73 2E |was `3.5' hours.|
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00000E70: 20 68 6F 75 72 73 2C 20 74 68 65 79 20 77 65 72 | hours, they wer|
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00000EA0: 65 73 00 32 36 32 2E 35 00 62 6F 79 00 44 61 76 |es.262.5.boy.Dav|
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00000ED0: 72 69 61 6E 00 64 00 44 61 76 65 27 73 00 26 76 |rian.d.Dave's.&v|
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A @Q{}@DG04&D(1,U/MEAS)&C(2,{})&C(3,{})
&D(4,TOT.)&D(5,RATE)&D(10,TIME)&D(15,DIS
T.)@RREAD@PREAD THE WHOLE PROBLEM. THINK
: WHAT ARE THE FACTS? WHAT IS BEING ASK
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{}&H@I(0) @RPLAN@PLET D{}={} DIST. AND
D{} = {} DIST. WRITE AN EQUATION TO RELA
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HEY HEADED IN OPPOSITE DIRECTIONS, SO TH
E SUM OF THEIR DISTANCES IS EQUAL TO THE
TOTAL DISTANCE.@H`{}' SHOWS THAT THE SU
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AL DISTANCE.@I(20,C0, )@PONE ANSWER IS `
{}'. CHANGE YOUR ANSWER IF IT IS NOT EQU
IVALENT. (PRESS RETURN).@HTHEY HEAD IN O
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ISTANCES IS EQUAL TO THE TOTAL DISTANCE.
@H`{}' SHOWS THAT THE SUM OF THEIR DISTA
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0,C0, )@RDATA ENTRY@PFILL IN THE UNITS B
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C.@HTHE RATE OF SPEED IN THIS PROBLEM, I
S MEASURED IN {}.@I(6,C{},{})@HTIME IS C
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(11,C{},{})@HDISTANCE IS COMMONLY MEASUR
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MILES (MI), KILOMETERS (KM), ETC.@HDIST
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I(16,C{},{})@PENTER THE FACTS FROM THE P
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{}@I(12,I,{})@H{}@HTHE TIME FOR {}@I(13,
I,{})@H{}@HTHE TOTAL DISTANCE BETWEEN TH
EM WAS {}.@I(19,I,{})@PUSE A VARIABLE TO
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.@HUSE A VARIABLE TO REPRESENT THE SLOWE
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LE SUCH AS `{}' TO REPRESENT {} RATE OF
SPEED.@I(7,I,{})@HREPRESENT {} RATE OF S
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TIME = DISTANCE@HRATE \F07* \F10 TIME
\F15= TOTAL DISTANCE \N`{}\F07* \F1
0 {}' \F15= {} DISTANCE @I(18,I,{})@RWH
OLE&D(20, )@PSUBSTITUTE YOUR EXPRESSIONS
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D{}+D{}= TOTAL@HD{}={}, D{}={} AND TOT
AL = {}@H{}@I(20,I,{})@S@RCOMPUTE@PSOLVE
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IDE OF THE EQUATION.@HTHE CALCULATOR SOL
VES EQUATIONS FOR YOU AND DISPLAYS THE S
TEPS IN THE SOLUTION.@I(20,I,&V={})@PNOW
YOU ARE READY TO ENTER YOUR ANSWERS IN
THE GRID. REMEMBER THE QUESTION.&Q{}&Q &
W(20)@H{} REPRESENTS {} RATE OF SPEED.@H
"&V" = {}@I(7,I,{})@S@H{} REPRESENTS {}
RATE OF SPEED.@H&V = {}@I(8,I,{})@S@RCHE
CK@PREREAD THE PROBLEM. CHECK YOUR ANSWE
RS. EVALUATE THE REMAINING EXPRESSIONS I
S THE GRID.@HSUBSTITUTE FOR "&V" IN THE
EXPRESSION FOR {} DISTANCE. THEN CALCULA
TE THE RESULT.@H{}, WHICH EQUALS {}.@I(1
7,I,{})@HSUBSTITUTE FOR "&V" IN THE EXPR
ESSION FOR {} DISTANCE. THEN CALCULATE T
HE RESULT.@H{}, WHICH EQUALS {}.@I(18,I
,{})&D(0,CHECK YOUR WORK. THE SUM OF {}
DISTANCES SHOULD EQUAL {}. GET READY FOR
A NEW PROBLEM.)@FBRIAN DRIVES 5 MI/HR F
ASTER THAN DAVE. THEY LEFT ATLANTA AT TH
E SAME TIME, DROVE IN OPPOSITE DIRECTION
S. AFTER 3.5 HOURS, THEY WERE 262.5 MI.
APART. HOW FAST DID EACH DRIVE?.DAVE.BRI
AN.THEY DROVE IN OPPOSITE DIRECTIONS AT
DIFFERENT RATES UNTIL THEY WERE 262.5 MI
APART..HOW FAST DID EACH DRIVE?.B.BRIAN
'S.D.DAVE'S.B.D.DD+DB = TOTAL.DB+DD = TO
TAL.DD+DB=TOTAL.MILES PER HOUR (`MI/HR')
.5.MI/HR.HOURS (`HR').2.HR.MILES (`MI').
.2.MI.DAVE DROVE FOR &H3.5 HOURS&H..DAVE
WAS `3.5' HOURS..3.5.BRIAN'S TIME IS TH
E SAME AS DAVE'S..BRIAN WAS `3.5' HOURS.
.3.5.&HAFTER 3.5 HOURS, THEY WERE 262.5
MILES APART&H..262.5 MILES.262.5.BOY.DAV
E DRIVES AT A SLOWER RATE THAN BRIAN.D.D
AVE'S.&V.BRIAN'S.DAVE'S.&QBRIAN DRIVES 5
MI/HR FASTER THAN DAVE&Q.`&V+5'.BRIAN D
RIVES 5 MI/HR FASTER THAN DAVE..&V+5.BOY
.`&V \F07* \F10 3.5' \F15= DAVE'S.3.5&
V.(&V+5).3.5.BRIAN'S.3.5(&V+5).B.D.D.B.D
.3.5&V.B.3.5(&V+5).262.5.DAVE'S DIST. \F
15+ BRIAN'S DIST. \F30= TOTAL \N `3.5&V
\F15+ 3.5(&V+5) \F30= 262.5'.3
.5&V+3.5(&V+5)=262.5.35.HOW FAST DID EAC
H OF THEM DRIVE?."&V".DAVE'S.`35'.35."&V
+5".BRIAN'S.35, AND 35+5, OR `40' IS BRI
AN'S RATE..40.DAVE'S.DAVE DROVE FOR 3.5&
V MILES.3.5* 35, OR `122.5' MILES.122.5.
BRIAN'S.BRIAN DROVE FOR 3.5(&V+5) MILES.
3.5*40, OR `140' MILES.140.DAVE AND BRIA
N'S.262.5 MILES.@FAT 8 AM TWO CARS LEFT
CLEVELAND HEADING IN OPPOSITE DIRECTIONS
. AT 11 AM THEY WERE 279 MILES APART. IF
CAR A DROVE 7 MI/HR SLOWER THAN CAR B,
HOW FAST DID EACH DRIVE?.CAR A.CAR B.THE
Y WERE 279 MILES APART AFTER DRIVING FRO
M 8 AM UNTIL 11 AM..HOW FAST DID EACH DR
IVE?.A.CAR A'S.B.CAR B'S.A.B.DA+DB= TOTA
L.DA+DB=TOTAL.DA+DB=TOTAL.MILES PER HOUR
(`MI/HR').4.MI/HR.HOURS (`HR').2.HR.MIL
ES (`MI').2.MI.BOTH OF THEM STARTED AT 8
AM AND STOPPED AT 11 AM..CAR A IS `3' H
OURS SINCE THERE ARE 3 HOURS FROM 8 TO 1
1..3.THE TIME IS THE SAME FOR CAR A AND
CAR B..CAR B IS `3' HOURS..3.&HTHEY WERE
279 MILES APART&H..`279' MILES.279.CAR.
CAR A TRAVELLED SLOWER THAN CAR B.A.CAR
A'S.&V.CAR B'S.CAR A'S.&HCAR A DROVE 7 M
I/HR SLOWER THAN CAR B&H..`&V+7'.CAR B W
ENT 7 MI/HR FASTER THAN CAR B..&V+7.CAR.
`&V \F07* \F10 3' \F15= CAR A'S.3&V.
(&V+7).3.CAR B'S.3(&V+7).A.B.A.B.A.3&V.B
.3(&V+7).270 MILES..CAR A'S DIST \F14+
CAR B'S DIST \F30= TOTAL \N `3&V \F14
+ 3(&V+7) \F30= 279'.3&V+3(&V+7)=279.4
3.HOW FAST DOES EACH DRIVE?."&V".CAR A'S
.43, CAR A'S RATE IS `43' MI/HR..43."&V+
7".CAR B'S.43 AND &V+7, OR `50' REPRESEN
TS CAR B'S RATE.50.CAR A'S.CAR A'S DISTA
NCE IS REPRESENTED BY 3&V.3*43, OR `129'
MILES.129.CAR B'S.CAR B'S DISTANCE IS R
EPRESENTED BY 3(&V+7).3*50, OR `150' MIL
ES.150.THEIR.279 MILES.@FTHE BLUE BOMBER
FLIES 3 TIMES AS FAST AS THE SILVER SLI
PPER. IF THEY FLY IN OPPOSITE DIRECTIONS
AND ARE 1,080 MILES APART AFTER FLYING
FOR 5 HOURS, HOW FAST DOES EACH PLANE FL
Y?.SILVER.BLUE.THEY FLY IN OPPOSITE DIRE
CTIONS FOR 5 HOURS AT DIFFERENT RATES..H
OW FAST DOES EACH PLANE FLY?.S.SILVER'S.
B.BLUE'S.S.B.DS+DB=TOTAL.DS+DB=TOTAL.DS+
DB=TOTAL.MILES PER HOUR (`MI/HR').4.MI/H
R.HOURS (`HR').2.HR.MILES (`MI')..2.MI.B
OTH PLANES FLEW FOR &H5 HOURS&H..THE SIL
VER SLIPPER WAS `5' HOURS..5.THE BLUE BO
MBER FLEW FOR THE SAME AMOUNT OF TIME AS
THE SILVER SLIPPER..THE BLUE BOMBER WAS
`5' HOURS..5.THEY ARE &H1,080 MILES APA
RT&H AFTER FLYING FOR 5 HOURS..`1,080' M
ILES.1080.PLANE.SILVER IS SLOWER THAN BL
UE.S.THE SILVER SLIPPER'S.&V.BLUE'S.SILV
ER'S.&QTHE BLUE BOMBER FLIES 3 TIMES AS
FAST AS THE SILVER SLIPPER.&Q."3&V".BLUE
FLIES 3 TIMES AS FAST AS SILVER..3&V.PL
ANE. `&V \F07* \F10 5' \F15= SILV
ER'S.5&V. 3&V.5.BLUE'S.15&V.S.B.S.B.S.5&
V.B.15&V.1080.SILVER'S DIST. \F15+ BLUE
'S DIST. \F30= TOTAL \N `5&V
\F15+ 15&V \F30= 1080' .5&V
+15&V=1080.54.HOW FAST DOES EACH PLANE F
LY?."&V".THE SILVER SLIPPER'S.54, SO SIL
VER FLIES `54' MI/HR..54."3&V".THE BLUE
BOMBER'S.54, SO BLUE FLIES 3*54, OR `162
' MI/HR..162.SILVER'S.&V=54 AND 5&V REPR
ESENTS SILVER'S DISTANCE, SO 5*54.`270'
IS SILVER'S DISTANCE.270.BLUE'S.&V=54 AN
D 15&V REPRESENTS BLUE'S DISTANCE, SO 15
*54.`810' IS BLUE'S DISTANCE.810.THEIR.1
080.|
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