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  __| |/ /_ | || |     __| (_)___| | __ (_)_ __   __| | _____  __
 / _` | '_ \| || |_   / _` | / __| |/ / | | '_ \ / _` |/ _ \ \/ /
| (_| | (_) |__   _| | (_| | \__ \   <  | | | | | (_| |  __/>  < 
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ATAMAKER

FILE INFORMATION

FILENAME(S): ATAMAKER

FILE TYPE(S): SEQ

FILE SIZE: 2.3K

FIRST SEEN: 2025-11-30 16:59:22

APPEARS ON: 1 disk(s)

FILE HASH

8d23c65fe76b1e85491b1dc30c40cb802955d7d38786ec719f7aa938f039eb0e

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DISK TITLE FILENAME FILE TYPE COLLECTION TRACK SECTOR ACTIONS
SERVANT V484 2 4 ATAMAKER SEQ High Voltage Complete C64 Collection 16 3 DOWNLOAD FILE

FILE CONTENT & ANALYSIS

00000000: C4 C1 D4 C1 CD C1 CB C5  D2 20 28 37 29 0D 0D D4  |......... (7)...|
00000010: 48 45 20 50 55 52 50 4F  53 45 20 4F 46 20 54 48  |HE PURPOSE OF TH|
00000020: 49 53 20 55 54 49 4C 49  54 59 20 49 53 20 54 4F  |IS UTILITY IS TO|
00000030: 20 52 45 41 44 20 54 48  45 20 43 4F 4E 54 45 4E  | READ THE CONTEN|
00000040: 54 53 20 4F 46 20 41 20  53 50 45 43 49 46 49 45  |TS OF A SPECIFIE|
00000050: 44 20 4D 45 4D 4F 52 59  20 52 41 4E 47 45 20 41  |D MEMORY RANGE A|
00000060: 4E 44 20 54 55 52 4E 20  49 54 20 49 4E 54 4F 20  |ND TURN IT INTO |
00000070: C4 C1 D4 C1 20 53 54 41  54 45 4D 45 4E 54 53 2E  |.... STATEMENTS.|
00000080: 20 20 D9 4F 55 20 43 41  4E 20 46 52 45 45 4C 59  |  .OU CAN FREELY|
00000090: 20 4D 45 52 47 45 20 C4  C1 D4 C1 20 53 54 41 54  | MERGE .... STAT|
000000A0: 45 4D 45 4E 54 53 20 49  4E 54 4F 20 41 4E 59 20  |EMENTS INTO ANY |
000000B0: C2 C1 D3 C9 C3 20 50 52  4F 47 52 41 4D 2E 20 20  |..... PROGRAM.  |
000000C0: CF 52 20 59 4F 55 20 43  41 4E 20 43 52 45 41 54  |.R YOU CAN CREAT|
000000D0: 45 20 41 20 53 54 41 4E  44 2D 41 4C 4F 4E 45 20  |E A STAND-ALONE |
000000E0: 50 52 4F 47 52 41 4D 20  43 4F 4E 54 41 49 4E 49  |PROGRAM CONTAINI|
000000F0: 4E 47 20 54 48 45 20 C4  C1 D4 C1 20 53 54 41 54  |NG THE .... STAT|
00000100: 45 4D 45 4E 54 53 20 4F  4E 4C 59 2E 20 20 C1 4C  |EMENTS ONLY.  .L|
00000110: 4C 20 50 41 52 41 4D 45  54 45 52 53 20 41 52 45  |L PARAMETERS ARE|
00000120: 20 53 50 45 43 49 46 49  45 44 20 49 4E 20 44 45  | SPECIFIED IN DE|
00000130: 43 49 4D 41 4C 2C 20 42  55 54 20 59 4F 55 20 43  |CIMAL, BUT YOU C|
00000140: 41 4E 20 55 53 45 20 48  45 58 41 44 45 43 49 4D  |AN USE HEXADECIM|
00000150: 41 4C 20 4E 55 4D 42 45  52 53 20 42 59 20 50 52  |AL NUMBERS BY PR|
00000160: 45 43 45 44 49 4E 47 20  54 48 45 20 4E 55 4D 42  |ECEDING THE NUMB|
00000170: 45 52 20 57 49 54 48 20  41 20 44 4F 4C 4C 41 52  |ER WITH A DOLLAR|
00000180: 20 53 49 47 4E 20 28 C5  56 45 4E 20 57 48 45 4E  | SIGN (.VEN WHEN|
00000190: 20 53 50 45 43 49 46 59  49 4E 47 20 4C 49 4E 45  | SPECIFYING LINE|
000001A0: 20 4E 55 4D 42 45 52 53  21 29 2E 20 20 D4 48 45  | NUMBERS!).  .HE|
000001B0: 20 50 52 4F 43 45 44 55  52 45 20 49 53 20 41 53  | PROCEDURE IS AS|
000001C0: 20 46 4F 4C 4C 4F 57 53  3A 0D 0D C2 C1 CE CB 3A  | FOLLOWS:......:|
000001D0: 0D D4 48 45 20 42 41 4E  4B 20 4E 55 4D 42 45 52  |..HE BANK NUMBER|
000001E0: 20 28 30 2D 31 35 29 20  46 52 4F 4D 20 57 48 49  | (0-15) FROM WHI|
000001F0: 43 48 20 54 4F 20 52 45  41 44 20 54 48 45 20 44  |CH TO READ THE D|
00000200: 45 53 49 52 45 44 20 44  41 54 41 2E 0D 0D D3 54  |ESIRED DATA....T|
00000210: 41 52 54 20 41 44 44 52  45 53 53 3A 0D D4 48 45  |ART ADDRESS:..HE|
00000220: 20 46 49 52 53 54 20 4D  45 4D 4F 52 59 20 41 44  | FIRST MEMORY AD|
00000230: 44 52 45 53 53 20 4F 46  20 54 48 45 20 44 41 54  |DRESS OF THE DAT|
00000240: 41 2E 0D 0D C5 4E 44 20  41 44 44 52 45 53 53 3A  |A....ND ADDRESS:|
00000250: 0D D4 48 45 20 4C 41 53  54 20 4D 45 4D 4F 52 59  |..HE LAST MEMORY|
00000260: 20 41 44 44 52 45 53 53  20 4F 46 20 54 48 45 20  | ADDRESS OF THE |
00000270: 44 41 54 41 2E 0D 0D C6  49 52 53 54 20 4C 49 4E  |DATA....IRST LIN|
00000280: 45 3A 0D D4 48 45 20 4C  49 4E 45 20 4E 55 4D 42  |E:..HE LINE NUMB|
00000290: 45 52 20 4F 46 20 54 48  45 20 46 49 52 53 54 20  |ER OF THE FIRST |
000002A0: 4C 49 4E 45 2E 0D 0D C9  4E 43 52 45 4D 45 4E 54  |LINE....NCREMENT|
000002B0: 3A 0D CC 49 4E 45 20 4E  55 4D 42 45 52 20 49 4E  |:..INE NUMBER IN|
000002C0: 43 52 45 4D 45 4E 54 2E  0D 0D CC 49 4E 45 20 4C  |CREMENT....INE L|
000002D0: 45 4E 47 54 48 3A 0D D4  48 45 20 4E 55 4D 42 45  |ENGTH:..HE NUMBE|
000002E0: 52 20 4F 46 20 44 41 54  41 20 45 4C 45 4D 45 4E  |R OF DATA ELEMEN|
000002F0: 54 53 20 50 45 52 20 4C  49 4E 45 2E 20 20 C9 46  |TS PER LINE.  .F|
00000300: 20 59 4F 55 20 53 50 45  43 49 46 59 20 41 20 47  | YOU SPECIFY A G|
00000310: 52 45 41 54 45 52 20 4E  55 4D 42 45 52 20 4F 46  |REATER NUMBER OF|
00000320: 20 44 41 54 41 20 45 4C  45 4D 45 4E 54 53 20 50  | DATA ELEMENTS P|
00000330: 45 52 20 4C 49 4E 45 20  54 48 41 4E 20 57 4F 55  |ER LINE THAN WOU|
00000340: 4C 44 20 41 43 54 55 41  4C 4C 59 20 46 49 54 2C  |LD ACTUALLY FIT,|
00000350: 20 54 48 45 20 44 41 54  41 4D 41 4B 45 52 20 57  | THE DATAMAKER W|
00000360: 49 4C 4C 20 41 4C 57 41  59 53 20 50 41 43 4B 20  |ILL ALWAYS PACK |
00000370: 41 53 20 4D 41 4E 59 20  44 41 54 41 20 45 4C 45  |AS MANY DATA ELE|
00000380: 4D 45 4E 54 53 20 41 53  20 50 4F 53 53 49 42 4C  |MENTS AS POSSIBL|
00000390: 45 20 4F 4E 20 45 41 43  48 20 4C 49 4E 45 20 41  |E ON EACH LINE A|
000003A0: 4E 44 20 50 4C 41 43 45  20 54 48 45 20 52 45 53  |ND PLACE THE RES|
000003B0: 54 20 4F 4E 20 54 48 45  20 4E 45 58 54 20 4C 49  |T ON THE NEXT LI|
000003C0: 4E 45 20 28 57 48 49 43  48 20 49 4E 20 54 55 52  |NE (WHICH IN TUR|
000003D0: 4E 20 57 49 4C 4C 20 42  45 20 41 53 20 4C 4F 4E  |N WILL BE AS LON|
000003E0: 47 20 41 53 20 50 4F 53  53 49 42 4C 45 29 2E 0D  |G AS POSSIBLE)..|
000003F0: 0D D4 59 50 45 A0 28 31  2D 35 29 3A 0D D4 48 49  |..YPE.(1-5):..HI|
00000400: 53 20 57 49 4C 4C 20 44  45 54 45 52 4D 49 4E 45  |S WILL DETERMINE|
00000410: 20 48 4F 57 20 54 48 45  20 4E 55 4D 42 45 52 53  | HOW THE NUMBERS|
00000420: 20 49 4E 20 54 48 45 20  44 41 54 41 20 53 54 41  | IN THE DATA STA|
00000430: 54 45 4D 45 4E 54 53 20  57 49 4C 4C 20 42 45 20  |TEMENTS WILL BE |
00000440: 52 45 50 52 45 53 45 4E  54 45 44 2E 20 20 D4 48  |REPRESENTED.  .H|
00000450: 45 52 45 20 41 52 45 20  46 49 56 45 20 54 59 50  |ERE ARE FIVE TYP|
00000460: 45 53 20 4F 46 20 44 41  54 41 20 53 54 41 54 45  |ES OF DATA STATE|
00000470: 4D 45 4E 54 53 20 41 56  41 49 4C 41 42 4C 45 20  |MENTS AVAILABLE |
00000480: 46 4F 52 20 4D 41 58 49  4D 55 4D 20 46 4C 45 58  |FOR MAXIMUM FLEX|
00000490: 49 42 49 4C 49 54 59 3A  20 20 31 20 3D 20 44 45  |IBILITY:  1 = DE|
000004A0: 43 49 4D 41 4C 20 57 49  54 48 20 47 41 50 53 20  |CIMAL WITH GAPS |
000004B0: 28 32 35 31 2C 20 37 34  2C 20 38 36 2C 20 45 54  |(251, 74, 86, ET|
000004C0: 43 2E 29 2C 20 32 20 3D  20 44 45 43 49 4D 41 4C  |C.), 2 = DECIMAL|
000004D0: 20 57 49 54 48 4F 55 54  20 47 41 50 53 20 28 32  | WITHOUT GAPS (2|
000004E0: 35 31 2C 37 34 2C 38 36  2C 29 2C 20 33 20 3D 20  |51,74,86,), 3 = |
000004F0: 48 45 58 20 57 49 54 48  20 47 41 50 53 20 28 46  |HEX WITH GAPS (F|
00000500: 42 2C 20 34 41 2C 20 35  36 2C 20 29 2C 20 34 20  |B, 4A, 56, ), 4 |
00000510: 3D 20 48 45 58 20 57 49  54 48 4F 55 54 20 47 41  |= HEX WITHOUT GA|
00000520: 50 53 20 28 46 42 2C 34  41 2C 35 36 2C 29 2C 20  |PS (FB,4A,56,), |
00000530: 35 20 3D 20 48 45 58 20  57 49 54 48 4F 55 54 20  |5 = HEX WITHOUT |
00000540: 47 41 50 53 2C 20 4E 4F  52 20 43 4F 4D 4D 41 53  |GAPS, NOR COMMAS|
00000550: 20 28 46 42 34 41 35 36  29 2E 20 20 D4 48 45 20  | (FB4A56).  .HE |
00000560: 4C 41 54 54 45 52 20 49  53 20 50 4F 53 53 49 42  |LATTER IS POSSIB|
00000570: 4C 45 20 42 45 43 41 55  53 45 20 48 45 58 20 56  |LE BECAUSE HEX V|
00000580: 41 4C 55 45 53 20 41 52  45 20 41 4C 57 41 59 53  |ALUES ARE ALWAYS|
00000590: 20 54 57 4F 20 43 48 41  52 41 43 54 45 52 53 20  | TWO CHARACTERS |
000005A0: 4C 4F 4E 47 2C 20 53 4F  20 54 48 45 59 20 43 41  |LONG, SO THEY CA|
000005B0: 4E 20 42 45 20 53 45 50  41 52 41 54 45 44 20 42  |N BE SEPARATED B|
000005C0: 59 20 55 53 49 4E 47 20  CD C9 C4 24 2E 20 20 D0  |Y USING ...$.  .|
000005D0: 4C 45 41 53 45 20 55 53  45 20 54 48 49 53 20 46  |LEASE USE THIS F|
000005E0: 55 4E 43 54 49 4F 4E 20  41 4E 44 20 53 45 45 20  |UNCTION AND SEE |
000005F0: 54 48 45 20 C2 C1 D3 C9  C3 20 50 52 4F 47 52 41  |THE ..... PROGRA|
00000600: 4D 20 49 54 20 43 52 45  41 54 45 53 2E 20 20 D4  |M IT CREATES.  .|
00000610: 48 49 53 20 56 41 52 49  41 4E 54 20 49 53 20 54  |HIS VARIANT IS T|
00000620: 48 45 20 4D 4F 53 54 20  43 4F 4D 50 41 43 54 2C  |HE MOST COMPACT,|
00000630: 20 42 55 54 20 41 54 20  54 48 45 20 53 41 4D 45  | BUT AT THE SAME|
00000640: 20 54 49 4D 45 20 54 48  45 20 53 4C 4F 57 45 53  | TIME THE SLOWES|
00000650: 54 2E 20 20 D4 59 50 45  20 32 20 49 53 20 54 48  |T.  .YPE 2 IS TH|
00000660: 45 20 46 41 53 54 45 53  54 20 54 4F 20 52 55 4E  |E FASTEST TO RUN|
00000670: 2E 20 20 D0 4C 45 41 53  45 20 4E 4F 54 45 20 54  |.  .LEASE NOTE T|
00000680: 48 41 54 20 54 59 50 45  53 20 33 2C 20 34 20 41  |HAT TYPES 3, 4 A|
00000690: 4E 44 20 35 20 43 4F 4E  54 41 49 4E 20 48 45 58  |ND 5 CONTAIN HEX|
000006A0: 41 44 45 43 49 4D 41 4C  20 4E 55 4D 42 45 52 53  |ADECIMAL NUMBERS|
000006B0: 2C 20 41 4E 44 20 49 53  20 54 48 45 52 45 42 59  |, AND IS THEREBY|
000006C0: 20 4E 4F 54 20 55 53 41  42 4C 45 20 49 46 20 54  | NOT USABLE IF T|
000006D0: 48 45 20 52 45 53 55 4C  54 49 4E 47 20 50 52 4F  |HE RESULTING PRO|
000006E0: 47 52 41 4D 20 49 53 20  54 4F 20 42 45 20 52 55  |GRAM IS TO BE RU|
000006F0: 4E 20 49 4E 20 36 34 20  4D 4F 44 45 2E 0D 0D C1  |N IN 64 MODE....|
00000700: 20 4C 49 54 54 4C 45 20  54 49 50 3A 20 20 D3 4F  | LITTLE TIP:  .O|
00000710: 4D 45 54 49 4D 45 53 20  49 54 20 57 4F 55 4C 44  |METIMES IT WOULD|
00000720: 20 42 45 20 50 52 41 43  54 49 43 41 4C 20 54 4F  | BE PRACTICAL TO|
00000730: 20 4B 4E 4F 57 20 54 48  45 20 41 43 54 55 41 4C  | KNOW THE ACTUAL|
00000740: 20 41 44 44 52 45 53 53  20 45 41 43 48 20 44 41  | ADDRESS EACH DA|
00000750: 54 41 20 45 4C 45 4D 45  4E 54 20 57 41 53 20 54  |TA ELEMENT WAS T|
00000760: 41 4B 45 4E 20 46 52 4F  4D 2E 20 20 D4 48 49 53  |AKEN FROM.  .HIS|
00000770: 20 43 41 4E 20 42 45 20  41 43 43 4F 4D 50 4C 49  | CAN BE ACCOMPLI|
00000780: 53 48 45 44 20 42 59 20  55 53 49 4E 47 20 4C 49  |SHED BY USING LI|
00000790: 4E 45 20 4E 55 4D 42 45  52 53 20 49 4E 20 41 20  |NE NUMBERS IN A |
000007A0: 43 55 4E 4E 49 4E 47 20  57 41 59 3A 0D 0D C4 45  |CUNNING WAY:...E|
000007B0: 43 49 44 45 20 48 4F 57  20 4D 41 4E 59 20 44 41  |CIDE HOW MANY DA|
000007C0: 54 41 20 45 4C 45 4D 45  4E 54 53 20 59 4F 55 20  |TA ELEMENTS YOU |
000007D0: 57 49 53 48 20 54 4F 20  50 55 54 20 4F 4E 20 45  |WISH TO PUT ON E|
000007E0: 41 43 48 20 4C 49 4E 45  2E 0D CD 55 4C 54 49 50  |ACH LINE...ULTIP|
000007F0: 4C 59 20 54 48 45 20 4E  55 4D 42 45 52 20 42 59  |LY THE NUMBER BY|
00000800: 20 54 57 4F 2C 20 41 4E  44 20 53 55 42 54 52 41  | TWO, AND SUBTRA|
00000810: 43 54 20 54 48 45 20 52  45 53 55 4C 54 49 4E 47  |CT THE RESULTING|
00000820: 20 46 49 47 55 52 45 20  46 52 4F 4D 20 54 48 45  | FIGURE FROM THE|
00000830: 20 53 54 41 52 54 20 41  44 44 52 45 53 53 2E 0D  | START ADDRESS..|
00000840: D3 50 45 43 49 46 59 20  54 48 45 20 52 45 53 55  |.PECIFY THE RESU|
00000850: 4C 54 49 4E 47 20 46 49  47 55 52 45 20 41 53 20  |LTING FIGURE AS |
00000860: 49 4E 49 54 49 41 4C 20  4C 49 4E 45 20 4E 55 4D  |INITIAL LINE NUM|
00000870: 42 45 52 2E 0D D4 48 45  4E 20 55 53 45 20 54 48  |BER...HEN USE TH|
00000880: 45 20 53 41 4D 45 20 56  41 4C 55 45 20 46 4F 52  |E SAME VALUE FOR|
00000890: 20 4C 49 4E 45 20 4E 55  4D 42 45 52 20 49 4E 43  | LINE NUMBER INC|
000008A0: 52 45 4D 45 4E 54 20 41  53 20 54 48 45 20 4E 55  |REMENT AS THE NU|
000008B0: 4D 42 45 52 20 4F 46 20  44 41 54 41 20 45 4C 45  |MBER OF DATA ELE|
000008C0: 4D 45 4E 54 53 20 59 4F  55 20 44 45 43 49 44 45  |MENTS YOU DECIDE|
000008D0: 44 20 54 4F 20 50 55 54  20 4F 4E 20 45 41 43 48  |D TO PUT ON EACH|
000008E0: 20 4C 49 4E 45 2E 0D 0D  CE 4F 57 2C 20 45 41 43  | LINE....OW, EAC|
000008F0: 48 20 4C 49 4E 45 20 4E  55 4D 42 45 52 20 57 49  |H LINE NUMBER WI|
00000900: 4C 4C 20 53 48 4F 57 20  54 48 45 20 41 43 54 55  |LL SHOW THE ACTU|
00000910: 41 4C 20 41 44 44 52 45  53 53 20 4F 46 20 54 48  |AL ADDRESS OF TH|
00000920: 45 20 46 49 52 53 54 20  44 41 54 41 20 45 4C 45  |E FIRST DATA ELE|
00000930: 4D 45 4E 54 20 4F 4E 20  54 48 41 54 20 4C 49 4E  |MENT ON THAT LIN|
00000940: 45 2E 0D                                          |E..             |
DATAMAKER (7)..THE PURPOSE OF THIS UTILI
TY IS TO READ THE CONTENTS OF A SPECIFIE
D MEMORY RANGE AND TURN IT INTO DATA STA
TEMENTS.  YOU CAN FREELY MERGE DATA STAT
EMENTS INTO ANY BASIC PROGRAM.  OR YOU C
AN CREATE A STAND-ALONE PROGRAM CONTAINI
NG THE DATA STATEMENTS ONLY.  ALL PARAME
TERS ARE SPECIFIED IN DECIMAL, BUT YOU C
AN USE HEXADECIMAL NUMBERS BY PRECEDING 
THE NUMBER WITH A DOLLAR SIGN (EVEN WHEN
 SPECIFYING LINE NUMBERS!).  THE PROCEDU
RE IS AS FOLLOWS:..BANK:.THE BANK NUMBER
 (0-15) FROM WHICH TO READ THE DESIRED D
ATA...START ADDRESS:.THE FIRST MEMORY AD
DRESS OF THE DATA...END ADDRESS:.THE LAS
T MEMORY ADDRESS OF THE DATA...FIRST LIN
E:.THE LINE NUMBER OF THE FIRST LINE...I
NCREMENT:.LINE NUMBER INCREMENT...LINE L
ENGTH:.THE NUMBER OF DATA ELEMENTS PER L
INE.  IF YOU SPECIFY A GREATER NUMBER OF
 DATA ELEMENTS PER LINE THAN WOULD ACTUA
LLY FIT, THE DATAMAKER WILL ALWAYS PACK 
AS MANY DATA ELEMENTS AS POSSIBLE ON EAC
H LINE AND PLACE THE REST ON THE NEXT LI
NE (WHICH IN TURN WILL BE AS LONG AS POS
SIBLE)...TYPE (1-5):.THIS WILL DETERMINE
 HOW THE NUMBERS IN THE DATA STATEMENTS 
WILL BE REPRESENTED.  THERE ARE FIVE TYP
ES OF DATA STATEMENTS AVAILABLE FOR MAXI
MUM FLEXIBILITY:  1 = DECIMAL WITH GAPS 
(251, 74, 86, ETC.), 2 = DECIMAL WITHOUT
 GAPS (251,74,86,), 3 = HEX WITH GAPS (F
B, 4A, 56, ), 4 = HEX WITHOUT GAPS (FB,4
A,56,), 5 = HEX WITHOUT GAPS, NOR COMMAS
 (FB4A56).  THE LATTER IS POSSIBLE BECAU
SE HEX VALUES ARE ALWAYS TWO CHARACTERS 
LONG, SO THEY CAN BE SEPARATED BY USING 
MID$.  PLEASE USE THIS FUNCTION AND SEE 
THE BASIC PROGRAM IT CREATES.  THIS VARI
ANT IS THE MOST COMPACT, BUT AT THE SAME
 TIME THE SLOWEST.  TYPE 2 IS THE FASTES
T TO RUN.  PLEASE NOTE THAT TYPES 3, 4 A
ND 5 CONTAIN HEXADECIMAL NUMBERS, AND IS
 THEREBY NOT USABLE IF THE RESULTING PRO
GRAM IS TO BE RUN IN 64 MODE...A LITTLE 
TIP:  SOMETIMES IT WOULD BE PRACTICAL TO
 KNOW THE ACTUAL ADDRESS EACH DATA ELEME
NT WAS TAKEN FROM.  THIS CAN BE ACCOMPLI
SHED BY USING LINE NUMBERS IN A CUNNING 
WAY:..DECIDE HOW MANY DATA ELEMENTS YOU 
WISH TO PUT ON EACH LINE..MULTIPLY THE N
UMBER BY TWO, AND SUBTRACT THE RESULTING
 FIGURE FROM THE START ADDRESS..SPECIFY 
THE RESULTING FIGURE AS INITIAL LINE NUM
BER..THEN USE THE SAME VALUE FOR LINE NU
MBER INCREMENT AS THE NUMBER OF DATA ELE
MENTS YOU DECIDED TO PUT ON EACH LINE...
NOW, EACH LINE NUMBER WILL SHOW THE ACTU
AL ADDRESS OF THE FIRST DATA ELEMENT ON 
THAT LINE..
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