MIXT2L4
FILE INFORMATION
FILENAME(S): MIXT2L4
FILE TYPE(S): PRG
FILE SIZE: 4.6K
FIRST SEEN: 2025-10-19 22:48:55
APPEARS ON: 1 disk(s)
FILE HASH
bd95d67572719e4749b54554781bea78f31766d48f02ff6690176a41afa1063e
FOUND ON DISKS (1 DISKS)
| DISK TITLE | FILENAME | FILE TYPE | COLLECTION | TRACK | SECTOR | ACTIONS |
|---|---|---|---|---|---|---|
| HHM 100785 44S1 | MIXT2L4 | PRG | Radd Maxx | 30 | 3 | DOWNLOAD FILE |
FILE CONTENT & ANALYSIS
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00000ED0: 69 74 68 20 61 20 31 30 25 20 69 6F 64 69 6E 65 |ith a 10% iodine|
00000EE0: 20 73 6F 6C 75 74 69 6F 6E 20 74 6F 20 63 72 65 | solution to cre|
00000EF0: 61 74 65 20 31 35 20 6F 75 6E 63 65 73 20 6F 66 |ate 15 ounces of|
00000F00: 20 61 6E 20 38 25 20 73 6F 6C 75 74 69 6F 6E 2E | an 8% solution.|
00000F10: 20 48 6F 77 20 6D 61 6E 79 20 6F 75 6E 63 65 73 | How many ounces|
00000F20: 20 6F 66 20 74 68 65 20 35 25 20 73 6F 6C 75 74 | of the 5% solut|
00000F30: 69 6F 6E 20 73 68 6F 75 6C 64 20 62 65 20 75 73 |ion should be us|
00000F40: 65 64 00 6F 7A 20 6F 66 20 70 75 72 65 00 26 68 |ed.oz of pure.&h|
00000F50: 41 20 35 25 20 69 6F 64 69 6E 65 20 73 6F 6C 75 |A 5% iodine solu|
00000F60: 74 69 6F 6E 20 69 73 20 6D 69 78 65 64 20 77 69 |tion is mixed wi|
00000F70: 74 68 20 61 20 31 30 25 20 69 6F 64 69 6E 65 20 |th a 10% iodine |
00000F80: 73 6F 6C 75 74 69 6F 6E 20 74 6F 20 63 72 65 61 |solution to crea|
00000F90: 74 65 20 31 35 20 6F 75 6E 63 65 73 20 6F 66 20 |te 15 ounces of |
00000FA0: 61 6E 20 38 25 20 73 6F 6C 75 74 69 6F 6E 26 68 |an 8% solution&h|
00000FB0: 00 48 6F 77 20 6D 61 6E 79 20 6F 75 6E 63 65 73 |.How many ounces|
00000FC0: 20 6F 66 20 74 68 65 20 35 25 20 73 6F 6C 75 74 | of the 5% solut|
00000FD0: 69 6F 6E 20 73 68 6F 75 6C 64 20 62 65 20 75 73 |ion should be us|
00000FE0: 65 64 00 2E 30 35 00 2E 30 35 00 60 2E 31 30 27 |ed..05..05.`.10'|
00000FF0: 00 2E 31 30 00 60 2E 30 38 27 00 2E 30 38 00 31 |..10.`.08'..08.1|
00001000: 35 20 6F 75 6E 63 65 73 20 6F 66 20 61 6E 20 38 |5 ounces of an 8|
00001010: 25 20 69 6F 64 69 6E 65 20 73 6F 6C 75 74 69 6F |% iodine solutio|
00001020: 6E 00 60 31 35 27 00 31 35 00 77 00 54 68 65 20 |n.`15'.15.w.The |
00001030: 74 6F 74 61 6C 20 76 6F 6C 75 6D 65 20 69 73 20 |total volume is |
00001040: 31 35 20 6F 75 6E 63 65 73 2E 20 49 66 20 74 68 |15 ounces. If th|
00001050: 65 72 65 20 61 72 65 20 22 26 76 22 20 6F 7A 73 |ere are "&v" ozs|
00001060: 20 6F 66 20 35 25 20 69 6F 64 69 6E 65 2C 20 60 | of 5% iodine, `|
00001070: 31 35 2D 26 76 27 20 69 73 20 74 68 65 20 76 6F |15-&v' is the vo|
00001080: 6C 75 6D 65 20 6F 66 20 74 68 65 20 53 74 72 6F |lume of the Stro|
00001090: 6E 67 20 73 6F 6C 75 74 69 6F 6E 00 28 31 35 2D |ng solution.(15-|
000010A0: 26 76 29 00 6F 75 6E 63 65 73 20 6F 66 20 69 6F |&v).ounces of io|
000010B0: 64 69 6E 65 00 60 2E 30 35 00 30 35 2A 26 76 00 |dine.`.05.05*&v.|
000010C0: 60 2E 31 00 28 31 35 2D 26 76 29 27 00 2E 31 2A |`.1.(15-&v)'..1*|
000010D0: 28 31 35 2D 26 76 29 00 69 6F 64 2E 00 20 20 2E |(15-&v).iod.. .|
000010E0: 30 38 20 20 20 20 20 20 5C 66 31 34 2A 20 20 20 |08 \f14* |
000010F0: 28 31 35 29 20 20 20 20 5C 66 32 35 3D 20 20 20 |(15) \f25= |
00001100: 60 31 2E 32 27 00 31 2E 32 00 20 60 2E 30 35 2A |`1.2'.1.2. `.05*|
00001110: 26 76 20 5C 66 31 31 2B 20 20 20 2E 31 28 31 35 |&v \f11+ .1(15|
00001120: 2D 26 76 29 20 20 5C 66 32 35 3D 20 20 31 2E 32 |-&v) \f25= 1.2|
00001130: 27 00 2E 30 35 26 76 2B 2E 31 28 31 35 2D 26 76 |'..05&v+.1(15-&v|
00001140: 29 3D 31 2E 32 00 36 00 48 6F 77 20 6D 61 6E 79 |)=1.2.6.How many|
00001150: 20 6F 75 6E 63 65 73 20 6F 66 20 35 25 20 73 6F | ounces of 5% so|
00001160: 6C 75 74 69 6F 6E 20 73 68 6F 75 6C 64 20 62 65 |lution should be|
00001170: 20 75 73 65 64 00 54 68 65 20 6E 75 6D 62 65 72 | used.The number|
00001180: 20 6F 66 20 6F 75 6E 63 65 73 20 6F 66 20 57 65 | of ounces of We|
00001190: 61 6B 20 73 6F 6C 75 74 69 6F 6E 20 69 73 20 74 |ak solution is t|
000011A0: 68 65 20 76 61 6C 75 65 20 6F 66 20 22 26 76 22 |he value of "&v"|
000011B0: 2E 20 26 76 20 3D 20 60 36 27 00 36 00 28 60 31 |. &v = `6'.6.(`1|
000011C0: 35 2D 26 76 27 29 00 31 35 2D 26 76 20 3D 20 31 |5-&v').15-&v = 1|
000011D0: 35 2D 36 20 3D 20 60 39 27 2E 00 39 00 6F 75 6E |5-6 = `9'..9.oun|
000011E0: 63 65 73 20 6F 66 20 70 75 72 65 20 69 6F 64 69 |ces of pure iodi|
000011F0: 6E 65 00 2E 30 35 2A 26 76 20 3D 20 2E 30 35 2A |ne..05*&v = .05*|
00001200: 36 20 3D 20 60 2E 33 27 2E 00 2E 33 00 6F 75 6E |6 = `.3'...3.oun|
00001210: 63 65 73 20 6F 66 20 70 75 72 65 20 69 6F 64 69 |ces of pure iodi|
00001220: 6E 65 00 2E 31 2A 28 31 35 2D 26 76 29 20 3D 20 |ne..1*(15-&v) = |
00001230: 2E 31 2A 28 31 35 2D 36 29 20 3D 20 2E 31 2A 39 |.1*(15-6) = .1*9|
00001240: 20 3D 20 60 2E 39 27 00 2E 39 00 7C 00 | = `.9'..9.|. |
A@Q{}?@DG02&D(1,WEAK SOL.)&D(2,STRNG SO
L.)&D(3,MIX)&D(4,UNIT STREN)&D(8,OZ OF S
OL)&D(12,{})@RREAD@PREAD THE WHOLE PROBL
EM. THINK: WHAT ARE THE FACTS? WHAT IS B
EING ASKED? (PRESS ANY KEY TO CONTINUE.)
@HWHAT ARE THE FACTS? {}.@HWHAT IS BEING
ASKED? &H{}&H?@I(0)@RDATA ENTRY@PFILL I
N THE GRID -- START WITH THE STRENGTHS P
ER UNIT.@HWHAT IS THE STRENGTH PER OUNCE
OF THE WEAK SOLUTION?@HTHE STRENGTH PER
OUNCE OF THE WEAK SOLUTION IS `{}' OUNC
ES.@I(5,I,{})@HWHAT IS THE STRENGTH PER
OUNCE OF THE STRONG SOLUTION?@HTHE STREN
GTH PER OUNCE OF THE STRONG SOLUTION IS
{} OUNCES.@I(6,I,{})@HWHAT IS THE STRENG
TH PER OUNCE OF THE MIXTURE?@HTHE STRENG
TH PER OUNCE OF THE MIX IS {} OUNCES.@I(
7,I,{})@PENTER THE FACTS FROM THE PROBLE
M INTO THE GRID.@HTHERE ARE &H{}&H.@HTHE
NUMBER OF OUNCES OF SOLUTION IN THE MIX
IS {}.@I(11,I,{})@PREPRESENT THE NUMBER
OF OUNCES OF WEAK AND STRONG SOLUTIONS
THAT WILL BE NEEDED.@HCHOOSE A VARIABLE
TO REPRESENT THE NUMBER OF OUNCES OF WEA
K SOLUTION.@HUSE ANY LETTER, SUCH AS `{}
' TO REPRESENT THE NUMBER OF OUNCES OF W
EAK SOLUTION.@I(9,I,&V)@HREPRESENT THE N
UMBER OF OUNCES OF THE STRONG SOLUTION I
N TERMS OF "&V" (THE NUMBER OF OUNCES OF
WEAK SOLUTION).@H{}.@I(10,I,{})@RPARTS@
PWRITE AN EXPRESSION TO REPRESENT THE NU
MBER OF {} CONTAINED IN EACH SOLUTION.@H
MULTIPLY THE UNIT STRENGTH BY THE # OF O
UNCES OF WEAK SOLUTION.@HUNIT STRNGTH\F1
4* # OF OZS \F25= OZ OF WEAK \N {}
\F14* &V' \F25= OZ OF WEAK@I(13
,I,.{})@HMULTIPLY THE UNIT STRENGTH BY #
OF OUNCES OF STRONG SOLUTION.@HUNIT STR
NGTH \F14* # OF OZS \F25= OZ OF STRO
NG \N {} \F14* {} \F25= OZ OF STR
ONG@I(14,I,{})@HMULTIPLY THE UNIT STRENG
TH BY THE # OF OUNCES IN THE MIXTURE.@HU
NIT STRNGTH \F14* # OF OZS \F25= OZ OF
{} \N {}@I(15,I,{}) @RWHOLE@PUSE THE GR
ID TO WRITE AN EQUATION RELATING THE PAR
TS (WEAK AND STRONG SOLUTIONS) TO THE WH
OLE (MIX).@H# OZ WEAK + # OZ STRONG = TO
TAL # OZ@H# OZ WEAK \F11+ # OZ STRONG \
F25= TOTAL \N{}@I(16,I,{})@S@RCOMPUTE@PS
OLVE THE EQUATION FOR "&V" (THE # OF OUN
CES OF WEAK SOL.). USE PENCIL AND PAPER,
OR USE THE CALCULATOR.@HISOLATE "&V" ON
ONE SIDE OF THE EQUATION.@HTHE CALCULAT
OR SOLVES THE EQUATIONS FOR YOU AND DISP
LAYS THE STEPS IN THE SOLUTION.@I(16,I,&
V={})@PNOW ENTER THE ANSWER(S) TO THE QU
ESTION. REMEMBER THE QUESTION. &Q{}?&Q&W
(16)@HTHE NUMBER OF OUNCES OF WEAK SOLUT
ION IS THE VALUE OF "&V".@H{}@I(9,I,{})@
S@RCHECK@PREREAD THE PROBLEM. CHECK YOUR
ANSWERS. REPLACE ALL VARIABLES IN THE G
RID.@HTHE NUMBER OF OUNCES OF STRONG SOL
UTION IS THE VALUE OF {}.@H{}@I(10,I,{})
@HSUBSTITUTE FOR "&V" IN THE EXPRESSION
FOR THE AMOUNT OF {} IN THE WEAK SOL. NO
W CALCULATE.@H{}@I(13,I,{})@HSUBSTITUTE
FOR "&V" IN THE EXPRESSION FOR THE AMOUN
T OF {} IN THE STRONG SOL. NOW CALCULAT
E.@H{}@I(14,I,{})&D(0, MAKE SURE THE SUM
OF THE WEAK AND STRONG SOLUTIONS EQUALS
THE TOTAL AMOUNT OF ACID IN THE MIXTURE
.)@FA CHEMIST NEEDS TO MAKE A 50% SULPHU
RIC ACID SOLUTION BY MIXING A 30% SOLUTI
ON AND A 60% SOLUTION. IF SHE NEEDS 120
OUNCES OF THE NEW SOLUTION, HOW MANY OUN
CES OF THE 30% SOLUTION ARE NEEDED.OZ OF
PURE.120 OUNCES OF A 50% SOLUTION IS TO
BE MADE BY MIXING A 30% SOLUTION WITH A
50% SOLUTION.HOW MANY OUNCES OF THE 30%
SOLUTION ARE NEEDED..30..3.`.60'..6.`.5
0'..50.120 OUNCES OF THE NEW SOLUTION,.`
120'.120.W.THERE ARE 120 OUNCES TOTAL. I
F THERE ARE "&V" OUNCES OF 30% ACID, `1
20-&V' WILL BE THE VOLUME OF THE STRONG
ACID.120-&V.ACID (IN OUNCES).`.3.3&V.`.6
.(120-&V)'..6*(120-&V).ACID..50 \
F14* 120 \F25= `60'..5*120.`.3&
V \F11+ .6(120-&V) \F23= 60'..3&V+.
6(120-&V)=60.40.HOW MANY OUNCES OF THE 3
0% SOLUTION IS NEEDED.THE NUMBER OF OUNC
ES OF WEAK SOLUTION IS THE VALUE OF "&V"
. &V = `40'.40.120-&V.120-&V = 120-40 =
`80'.80.ACID..3&V=.3*40 = `12'.12.ACID..
6*(120-&V)=.6*(120-40)=.6*80 = `48'.48.@
FA 5% IODINE SOLUTION IS MIXED WITH A 10
% IODINE SOLUTION TO CREATE 15 OUNCES OF
AN 8% SOLUTION. HOW MANY OUNCES OF THE
5% SOLUTION SHOULD BE USED.OZ OF PURE.&H
A 5% IODINE SOLUTION IS MIXED WITH A 10%
IODINE SOLUTION TO CREATE 15 OUNCES OF
AN 8% SOLUTION&H.HOW MANY OUNCES OF THE
5% SOLUTION SHOULD BE USED..05..05.`.10'
..10.`.08'..08.15 OUNCES OF AN 8% IODINE
SOLUTION.`15'.15.W.THE TOTAL VOLUME IS
15 OUNCES. IF THERE ARE "&V" OZS OF 5% I
ODINE, `15-&V' IS THE VOLUME OF THE STRO
NG SOLUTION.(15-&V).OUNCES OF IODINE.`.0
5.05*&V.`.1.(15-&V)'..1*(15-&V).IOD.. .
08 \F14* (15) \F25= `1.2'.1.
2. `.05*&V \F11+ .1(15-&V) \F25= 1.2
'..05&V+.1(15-&V)=1.2.6.HOW MANY OUNCES
OF 5% SOLUTION SHOULD BE USED.THE NUMBER
OF OUNCES OF WEAK SOLUTION IS THE VALUE
OF "&V". &V = `6'.6.(`15-&V').15-&V = 1
5-6 = `9'..9.OUNCES OF PURE IODINE..05*&
V = .05*6 = `.3'...3.OUNCES OF PURE IODI
NE..1*(15-&V) = .1*(15-6) = .1*9 = `.9'.
.9.|.
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