00000000: 01 08 0F 08 0A 00 52 41 44 49 55 53 B2 35 30 00 |......RADIUS.50.|
00000010: 20 08 14 00 4C 41 45 4E 47 44 45 4E B2 32 30 30 | ...LAENGDEN.200|
00000020: 00 33 08 1E 00 47 52 41 44 45 52 B2 28 31 38 30 |.3...GRADER.(180|
00000030: AD FF 29 00 47 08 28 00 52 44 49 41 4E 45 52 B2 |..).G.(.RDIANER.|
00000040: 28 FF AD 31 38 30 29 00 53 08 2D 00 52 45 53 54 |(..180).S.-.REST|
00000050: 25 B2 31 00 62 08 32 00 54 B2 28 52 41 AB 52 45 |%.1.b.2.T.(RA.RE|
00000060: 25 29 00 7A 08 34 00 54 54 B2 BA 28 28 52 41 AC |%).z.4.TT..((RA.|
00000070: 52 41 29 AB 28 54 AC 54 29 29 00 98 08 3C 00 8F |RA).(T.T))...<..|
00000080: 20 2A 20 55 44 52 45 47 4E 49 4E 47 20 41 46 20 | * UDREGNING AF |
00000090: 56 49 4E 4B 45 4C 20 2A 00 AB 08 46 00 56 49 4E |VINKEL *...F.VIN|
000000A0: 4B 45 4C B2 C1 28 54 54 AD 54 29 00 B8 08 4B 00 |KEL..(TT.T)...K.|
000000B0: 56 4F B2 56 49 AC 47 52 00 D4 08 50 00 42 55 45 |VO.VI.GR...P.BUE|
000000C0: 53 54 59 4B 4B 45 54 B2 52 41 AC 52 44 AC 28 56 |STYKKET.RA.RD.(V|
000000D0: 4F AC 32 29 00 E2 08 55 00 51 B2 BF 28 56 49 AC |O.2)...U.Q..(VI.|
000000E0: 32 29 00 06 09 5A 00 41 52 28 31 29 B2 28 52 41 |2)...Z.AR(1).(RA|
000000F0: AC 52 41 AD 32 29 3A 41 52 28 32 29 B2 28 42 55 |.RA.2):AR(2).(BU|
00000100: AD 52 41 AB 51 29 00 1C 09 64 00 41 52 45 41 4C |.RA.Q)...d.AREAL|
00000110: B2 41 52 28 31 29 AC 41 52 28 32 29 00 3F 09 6E |.AR(1).AR(2).?.n|
00000120: 00 52 55 4D 46 41 4E 47 25 B2 28 41 52 45 41 4C |.RUMFANG%.(AREAL|
00000130: AC 4C 41 45 4E 47 44 45 4E 29 AD 31 30 30 30 00 |.LAENGDEN).1000.|
00000140: 49 09 6F 00 9F 34 2C 34 3A 00 5B 09 70 00 8B 52 |I.o..4,4:.[.p..R|
00000150: 45 25 B2 31 A7 20 8D 31 31 31 31 00 62 09 71 00 |E%.1. .1111.b.q.|
00000160: 98 34 00 9C 09 72 00 98 34 2C 22 52 45 53 54 20 |.4...r..4,"REST |
00000170: 49 20 4D 4D 2E 20 3D 20 22 52 45 25 3B 22 20 20 |I MM. = "RE%;" |
00000180: 20 20 3D 20 52 45 53 54 20 49 20 4C 49 54 45 52 | = REST I LITER|
00000190: 20 4F 4C 49 45 20 3D 22 3B 52 55 25 00 AE 09 73 | OLIE =";RU%...s|
000001A0: 00 99 52 45 53 54 25 2C 52 55 25 2C 41 52 00 C0 |..REST%,RU%,AR..|
000001B0: 09 78 00 52 45 53 54 25 B2 52 45 53 54 25 AA 31 |.x.REST%.REST%.1|
000001C0: 00 D0 09 82 00 8B 52 45 53 54 25 B2 35 30 A7 80 |......REST%.50..|
000001D0: 00 DE 09 8C 00 A0 34 3A 20 20 20 89 35 30 00 0F |......4: .50..|
000001E0: 0A 57 04 98 34 2C C7 28 31 34 29 3B 22 54 41 42 |.W..4,.(14);"TAB|
000001F0: 45 4C 20 4F 56 45 52 20 52 45 53 54 20 41 46 20 |EL OVER REST AF |
00000200: 4F 4C 49 45 20 49 20 45 4E 20 54 41 4E 4B 22 00 |OLIE I EN TANK".|
00000210: 46 0A 58 04 98 34 2C C7 28 31 34 29 3B 22 4D 45 |F.X..4,.(14);"ME|
00000220: 44 20 45 4E 20 44 49 41 4D 45 54 45 52 20 50 5D |D EN DIAMETER P]|
00000230: 20 31 30 30 20 4D 4D 20 4F 47 20 45 4E 20 4C 5B | 100 MM OG EN L[|
00000240: 4E 47 44 45 20 22 00 63 0A 59 04 98 34 2C C7 28 |NGDE ".c.Y..4,.(|
00000250: 31 34 29 3B 22 50 5D 20 32 30 30 30 20 4D 4D 22 |14);"P] 2000 MM"|
00000260: 20 3A 8E 00 00 00 | :.... |
......RADIUS.50. ...LAENGDEN.200.3...GRA
DER.(180..).G.(.RDIANER.(..180).S.-.REST
%.1.B.2.T.(RA.RE%).Z.4.TT..((RA.RA).(T.T
))...<.. * UDREGNING AF VINKEL *...F.VIN
KEL.A(TT.T)...K.VO.VI.GR.T.P.BUESTYKKET.
RA.RD.(VO.2)...U.Q..(VI.2)...Z.AR(1).(RA
.RA.2):AR(2).(BU.RA.Q)...D.AREAL.AR(1).A
R(2).?.N.RUMFANG%.(AREAL.LAENGDEN).1000.
I.O..4,4:.[.P..RE%.1. .1111.B.Q..4...R..
4,"REST I MM. = "RE%;" = REST I LITER
OLIE =";RU%...S..REST%,RU%,AR...X.REST%
.REST%.1.P....REST%.50....... 4: .50..
.W..4,G(14);"TABEL OVER REST AF OLIE I E
N TANK".F.X..4,G(14);"MED EN DIAMETER P]
100 MM OG EN L[NGDE ".C.Y..4,G(14);"P]
2000 MM" :....
×
C64 Image
> CLICK IMAGE PREVIEW FOR FULL MODAL