DIST1L3
FILE INFORMATION
FILENAME(S): DIST1L3
FILE TYPE(S): PRG
FILE SIZE: 7.6K
FIRST SEEN: 2025-10-19 22:48:55
APPEARS ON: 1 disk(s)
FILE HASH
ddc38ce35880f761d1e94b119d4f4c48fb94cc92f73526ee9b30077c6ca4ab8e
FOUND ON DISKS (1 DISKS)
| DISK TITLE | FILENAME | FILE TYPE | COLLECTION | TRACK | SECTOR | ACTIONS |
|---|---|---|---|---|---|---|
| HHM 100785 43S1 | DIST1L3 | PRG | Radd Maxx | 21 | 1 | DOWNLOAD FILE |
FILE CONTENT & ANALYSIS
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00001DD0: 00 31 32 00 2E 32 35 00 2E 32 35 00 74 68 65 20 |.12..25..25.the |
00001DE0: 72 6F 62 69 6E 27 73 00 26 76 20 3D 20 2E 32 35 |robin's.&v = .25|
00001DF0: 2C 20 73 6F 20 35 20 2A 20 26 76 20 3D 20 35 20 |, so 5 * &v = 5 |
00001E00: 2A 20 2E 32 35 20 3D 20 60 31 2E 32 35 27 00 31 |* .25 = `1.25'.1|
00001E10: 2E 32 35 00 74 68 65 20 62 6C 75 65 20 6A 61 79 |.25.the blue jay|
00001E20: 27 73 00 26 76 20 3D 20 2E 32 35 2C 20 73 6F 20 |'s.&v = .25, so |
00001E30: 37 20 2A 20 26 76 20 3D 20 37 20 2A 20 2E 32 35 |7 * &v = 7 * .25|
00001E40: 20 3D 20 60 31 2E 37 35 27 00 31 2E 37 35 00 74 | = `1.75'.1.75.t|
00001E50: 68 65 20 62 69 72 64 73 27 00 33 00 7C 20 |he birds'.3.| |
A @Q{}@DG04&D(1,U/MEAS)&C(2,
{})&C(3,{})&D(4,TOT.)&D(5,RATE)&D(10,TIM
E)&D(15,DIST.)@RREAD@PREAD THE WHOLE PRO
BLEM. THINK: WHAT ARE THE FACTS? WHAT I
S BEING ASKED? (PRESS ANY KEY TO CONTINU
E.)@HWHAT ARE THE FACTS? {}@HWHAT IS BEI
NG ASKED? {}@I(0) @RPLAN@PLET D{} = {} D
IST. AND D{} = {} DIST. WRITE AN EQUATIO
N TO RELATE D{} AND D{} TO THE TOTAL DIS
T.@HTHEY {} IN OPPOSITE DIRECTIONS FOR T
HE SAME LENGTH OF TIME UNTIL THEY ARE {}
APART.@H{}@I(20,C0, )@PONE ANSWER IS `{
}'. CHANGE YOUR ANSWER IF IT IS NOT EQUI
VALENT. (PRESS RETURN)@HTHEY {} IN OPPOS
ITE DIRECTIONS FOR THE SAME LENGTH OF TI
ME UNTIL THEY ARE {} APART.@H{}@I(20,C0,
)@RDATA ENTRY@PFILL IN THE UNITS BY WHI
CH RATE, TIME AND DISTANCE ARE MEASURED.
(USE ABBREVIATED FORM.)@HRATE OF SPEED
IS COMMONLY MEASURED IN MILES PER HOUR(M
I/HR), METERS PER MINUTE(M/MIN), ETC.@HT
HE RATE OF SPEED IN THIS PROBLEM IS MEAS
URED IN {}.@I(6,C{},{})@HTIME IS COMMONL
Y MEASURED IN SECONDS (SEC), MINUTES (MI
N), HOURS (HR), DAYS (DA), ETC.@HTIME IN
THIS PROBLEM IS MEASURED IN {}.@I(11,C{
},{})@HDISTANCE IS COMMONLY MEASURED IN
FEET (FT), YARDS (YD), METERS (M), MILES
(MI), KILOMETERS (KM), ETC.@HDISTANCE I
N THIS PROBLEM, IS MEASURED IN {}.@I(16,
C{},{})@PENTER THE FACTS FROM THE PROBLE
M INTO THE GRID.@H{}.@HTHE RATE OF SPEED
FOR {} IS {}.@I(7,I,{})@H{}.@HTHE RATE
OF SPEED FOR {} IS {}.@I(8,I,{})@HENTER
THE DISTANCE BETWEEN {}.@HTHEY ARE {} AP
ART.@I(19,I,{})@PUSE A VARIABLE TO REPRE
SENT THE AMOUNT OF TIME EACH {} TRAVELS.
@HUSE THE SAME VARIABLE TO REPRESENT BOT
H {} TIME.@HUSE A VARIBLE, SUCH AS `T' T
O REPRESENT {} TIME.@I(12,I,&V)@H{} FOR
THE SAME AMOUNT OF TIME AS {}.@HUSE THE
SAME VARIABLE, `&V' TO REPRESENT {} TIME
.@I(13,I,&V)@RPARTS@PWRITE AN EXPRESSION
TO REPRESENT THE DISTANCE TRAVELLED BY
EACH {}.@HRATE*TIME = DISTANCE@HRATE \F
06* \F08TIME \F14= DISTANCE \N`{} \F0
6* \F08{}' \F14= {} DISTANCE@I(17,I,{})
@HRATE*TIME = DISTANCE@HRATE \F06* \F0
8TIME \F14= DISTANCE \N`{} \F06* \F08{
}' \F14= {} DISTANCE@I(18,I,{})@RWHOLE&
D(20, )@PSUBSTITUTE YOUR EXPRESSIONS FOR
D{}, D{} AND TOTAL IN THE EQUATION: \N
D{}+D{} = TOTAL@HD{}={}, D{}={} AND TO
TAL={}.@H{} DIST. \F15+{} DIST. \F30= TO
TAL \N `{}'@I(20,I,{})@S@RCOMPUTE @PSOL
VE THE EQUATION FOR "&V". USE PAPER AND
PENCIL AND ENTER THE FINAL EQUATION, OR
USE THE CALCULATOR.@HISOLATE "&V" ON ONE
SIDE OF THE EQUATION.@HTHE CALCULATOR S
OLVES EQUATIONS FOR YOU AND DISPLAYS THE
STEPS IN THE SOLUTION.@I(20,I,&V={})@PN
OW YOU ARE READY TO ENTER YOUR ANSWERS I
N THE GRID. REMEMBER THE QUESTION.&Q{}&Q
@H{} AND {} TIMES ARE BOTH EQUAL TO THE
VALUE OF "&V".@H&V={} ,SO {}@I({},I,{})@
S&D(13,{})@RCHECK@PREREAD THE PROBLEM. C
HECK YOUR ANSWERS. EVALUATE THE REMAININ
G EXPRESSIONS IN THE GRID.@HSUBSTITUTE F
OR "&V" IN THE EXPRESSION FOR {} DISTANC
E. THEN CALCULATE THE RESULT.@H{}@I(17,I
,{})@HSUBSTITUTE FOR "&V" IN THE EXPRESS
ION FOR {} DISTANCE. THEN CALCULATE THE
RESULT.@H{}.@I(18,I,{})&D(0,CHECK YOUR W
ORK. THE SUM OF {} DISTANCES SHOULD BE {
}. GET READY FOR A NEW PROBLEM.)@FJANE A
ND ALICE LEFT MONTEREY BAY AT 4 P.M. JAN
E DROVE NORTH AT 48 MI/HR AND ALICE DROV
E SOUTH AT 45 MI/HR. HOW LONG DID IT TAK
E THEM TO GET 372 MILES APART?.JANE.ALIC
E.JANE DROVE NORTH AT 48 MI/HR AND ALICE
DROVE SOUTH AT 45 MI/HR UNTIL THEY WERE
372 MILES APART..&HHOW LONG DID IT TAKE
THEM TO GET 372 MILES APART?&H.J.JANE'S
.A.ALICE'S.J.A.DRIVE.372 MILES.`DJ+DA =
TOTAL' SHOWS THAT THE SUM OF THEIR DISTA
NCES WILL EQUAL 372 MILES..DJ+DA = TOTAL
.DRIVE.372 MILES.`DJ+DA = TOTAL' SHOWS T
HAT THE SUM OF THEIR DISTANCES WILL EQUA
L 372 MILES..MILES PER HOUR (`MI/HR').5.
MI/HR.HOURS (`HR').2.HR.MILES (`MI').2.M
I.&HJANE DROVE NORTH AT 48 MI/HR&H.JANE.
'48' MI/HR.48.&HALICE DROVE SOUTH AT 45
MI/HR&H.ALICE.`45' MI/HR.45.JANE AND ALI
CE.`372' MILES.372.GIRL.GIRLS'.JANE'S.AL
ICE DRIVES.JANE.ALICE'S.GIRL.48.&V.JANE'
S.48&V.45.&V.ALICE'S.45&V.J.A.J.A.J.48&V
.A.45&V.372.JANE'S.ALICE'S.48&V \F1
5+ 45&V \F30= 372.48&V+45&V=3
72.4.HOW LONG DID IT TAKE THEM TO GET 37
2 MILES APART?.JANE.ALICE'S.4.JANE DROVE
FOR `4' HOURS..12.4.4.JANE'S.&V = 4, AN
D 48*4 = `192'.192.ALICE'S.&V = 4, AND 4
5*4 = `180'.180.JANE'S AND ALICE'S.372.@
FJESSICA SWIMS 25 YD/MIN AND AMANDA SWIM
S 30 YD/MIN. IF THEY START AT THE SAME S
POT AND SWIM IN OPPOSITE DIRECTIONS, HOW
LONG WILL IT TAKE THEM TO GET 1320 YARD
S APART?.JESSICA.AMANDA.THEY SWIM AT DIF
FERENT RATES IN OPPOSITE DIRECTIONS FOR
THE SAME LENGTH OF TIME..&HHOW LONG WILL
IT TAKE THEM TO GET 1320 YARDS APART?&H
.J.JESSICA'S.A.AMANDA'S.J.A.SWIM.1320 YA
RDS.`DJ+DA = TOTAL' SHOWS THAT THE TOTAL
DISTANCE BETWEEN THEM IS THE SUM OF THE
IR DISTANCES..DJ+DA = TOTAL.SWIM.1320 YA
RDS.`DJ+DA = TOTAL' SHOWS THAT THE TOTAL
DISTANCE BETWEEN THEM IS THE SUM OF THE
IR DISTANCES..`YD/MIN'.5.YD/MIN.MINUTES
(`MIN').3.MIN.YARDS (`YD').2.YD.&HJESSIC
A SWIMS 25 YD/MIN&H.JESSICA.`25' YD/MIN.
25.&HAMANDA SWIMS 30 YD/MIN&H.AMANDA.`30
' YD/MIN.30.JESSICA AND AMANDA.`1320' YA
RDS.1320.GIRL.GIRLS'.JESSICA'S.AMANDA SW
IMS.JESSICA.AMANDA'S.GIRL.25.&V.JESSICA'
S.25&V.30.&V.AMANDA'S.30&V.J.A.J.A.J.25&
V.A.30&V.1320.JESSIE'S.AMANDA'S. 25&V
\F15+ 30&V \F30= 1320.25&V+30&V=1320.
24.HOW LONG WILL IT TAKE THEM TO GET 132
0 YARDS APART?.JESSICA.AMANDA'S.24.JESSI
CA SWAM FOR `24' MINUTES.12.24.24.JESSIC
A'S.&V = 24, SO 25&V = 25 * 24 = `600'.6
00.AMANDA'S.&V = 24, SO 30&V = 30 * 24 =
'720'.720.JESSICA AND AMANDA'S.1320.@FA
N EXPRESS TRAIN LEFT KANSAS CITY GOING S
OUTH AT 60 MI/HR. AT THE SAME TIME, A LO
CAL TRAIN LEFT KANSAS CITY GOING NORTH A
T 42 MI/HR. IN HOW MANY HOURS WERE THEY
1530 MILES APART?.EXPRESS.LOCAL.THE TRAI
NS HEADED IN OPPOSITE DIRECTIONS AT DIFF
ERENT RATES..&HIN HOW MANY HOURS WERE TH
EY 1530 MILES APART?&H.E.EXPRESS.L.LOCAL
.E.L.TRAVEL.1530 MILES.`DE+DL = TOTAL' S
HOWS THAT THE SUM OF THEIR DISTANCES IS
EQUAL TO THE TOTAL DISTANCE..DE+DL = TOT
AL.TRAVEL.1530.`DE+DL = TOTAL' SHOWS THA
T THE SUM OF THEIR DISTANCES IS EQUAL TO
THE TOTAL DISTANCE..`MI/HR'.4.MI/HR.HOU
RS (`HR').2.HR.MILES (`MI').2.MI.THE EXP
RESS TRAIN TRAVELS AT &H60 MI/HR&H.THE E
XPRESS TRAIN.`60' MI/HR.60.THE LOCAL TRA
IN TRAVELS AT `42' MI/HR.THE LOCAL TRAIN
.`42' MI/HR.42.THE EXPRESS AND LOCAL TRA
INS.`1530' MILES.1530.TRAIN.TRAINS'.THE
EXPRESS TRAIN'S.THE LOCAL TRAIN TRAVELS.
THE EXPRESS TRAIN.THE LOCAL TRAIN'S.TRAI
N.60.&V.EXPRESS.60&V.42.&V.LOCAL.42&V.E.
L.E.L.E.60&V.L.42&V.1530.EXPRESS.LOCAL.6
0&V \F15+ 42&V \F30= 1530.60&V+42&V=15
30.15.IN HOW MANY HOURS WERE THEY 1530 M
ILES APART?.THE EXPRESS.LOCAL.15.THE TRA
INS TRAVELLED FOR `15' HOURS..12.15.15.E
XPRESS TRAIN'S.&V = 15, SO 60 * &V = 60
* 15 = `900'.900.LOCAL TRAIN'S.&V = 15,
SO 42 * &V = 42 * 15 = `630'.630.THE TRA
INS'.1530.@FA ROBIN, FLYING 5 KM/HR AND
A BLUE JAY, FLYING 7 KM/HR, FLY IN OPPOS
ITE DIRECTIONS. HOW LONG WILL IT TAKE TH
EM TO GET 3 KILOMETERS APART?.ROBIN.BLUE
JAY.THEY FLY IN OPPOSITE DIRECTIONS FOR
THE SAME AMOUNT OF TIME UNTIL THEY ARE
3 KM. APART..&HHOW LONG WILL IT TAKE THE
M TO GET 3 KILOMETERS APART?&H.R.ROBIN'S
.B.BLUE JAY'S.R.B.FLY.3 KM..`DR+DB = TOT
AL' SHOWS THAT THE SUM OF THE BIRD'S DIS
TANCES IS EQUAL TO THE TOTAL DISTANCE..D
R+DB = TOTAL.FLY.3 KM..`DR+DB = TOTAL' S
HOWS THAT THE SUM OF THE BIRD'S DISTANCE
S IS EQUAL TO THE TOTAL DISTANCE..`KM/HR
'.4.KM/HR.HOURS (`HR').2.HR.KILOMETERS (
`KM').2.KM.THE ROBIN FLIES &H5 KM/HR&H.R
OBIN.`5' KM/HR.5.THE BLUE JAY FLIES &H7
KM/HR&H.BLUE JAY.`7' KM/HR.7.THE ROBIN A
ND THE BLUE JAY.`3' KILOMETERS.3.BIRD.BI
RDS'.THE ROBIN'S.THE BLUE JAY FLIES.THE
ROBIN.THE BLUE JAY'S.BIRD.5.&V.ROBIN'S.5
&V.7.&V.BLUE JAY'S.7&V.R.B.R.B.R.5 * &V.
B.7 * &V.3.ROBIN'S.BLUE J'S.5&V \F15+ 7
&V \F30= 3.5&V+7&V=3..25.HOW LONG WILL
IT TAKE THEM TO GET 3 KILOMETERS APART?.
THE ROBIN'S.THE BLUE JAY'S..25.THE BIRDS
FLEW `.25' OR `1/4' OF AN HOUR..12..25.
.25.THE ROBIN'S.&V = .25, SO 5 * &V = 5
* .25 = `1.25'.1.25.THE BLUE JAY'S.&V =
.25, SO 7 * &V = 7 * .25 = `1.75'.1.75.T
HE BIRDS'.3.|
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